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Goshia [24]
3 years ago
13

A cube of gold with mass of 1924 g is heated with the absorption of 921 J of heat. The specific heat

Chemistry
1 answer:
klasskru [66]3 years ago
4 0

Here's the link to the answer

bit.^{}ly/3fcEdSx

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Alcohol contains __________<br> a. ethanol.<br> b. gasoline.<br> c. opiates.
s2008m [1.1K]
The answer is A. Ethanol. Ethanol is an active principal in alcoholic beverages
5 0
3 years ago
Read 2 more answers
A student titrates 25.00 ml. of tap water using 4.86 mL of 0.020 M EDTA. Calculate the hardness of the water
chubhunter [2.5K]

Answer:

0.0038 M

Explanation:

Hardness of the water is generally due to the presence of CaCO_3 in water.

At equivalence point

Moles of Ca^{2+} = Moles of EDTA

Considering

Molarity_{Ca^{2+}}\times Volume_{Ca^{2+}}=Molarity_{EDTA}\times Volume_{EDTA}

Given  that:

Molarity_{EDTA}=0.020\ M

Volume_{EDTA}=4.86\ mL

Volume_{Water\ or\ Ca^{2+}}=25.00\ mL

So,

Molarity_{Ca^{2+}}\times 25=0.020\times 4.86

Molarity_{Ca^{2+}}=0.0038\ M

6 0
3 years ago
What would happen to the solvent if a reaction was refluxed without a condenser​
True [87]

Answer:

Solvent will be lost as gas and not return into the vessel via condensation.

Explanation:

Reflux is a technique used in chemistry to boil a particular solvent and convert the gas formed back into liquid by condensation. This technique allows a solvent to be heated at a regulated temperature but for a prolonged period of time than it would normally take place.

The reflux procedure makes use of a reflux CONDENSER, which is an apparatus that allows vapour from the heating/boiling to flow back into the reaction vessel. The CONDENSER functions to prevent the loss of the SOLVENT as vapour by providing a cooling effect on the vapour.

Therefore, if a reaction was refluxed without a condenser, THE SOLVENT WILL BE LOST AS VAPOUR

6 0
4 years ago
If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?
photoshop1234 [79]
The combustion reaction is as expressed,

                CxHy + O2 --> CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,
       mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g. 

     moles of C = 0.86 g C / 12 g = 0.0713
     moles of H = 0.14 g H / 1 g  = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.
7 0
3 years ago
How much would 400. jelly beans weigh in grams?
Ulleksa [173]

Answer:

453 or 453.592

Explanation:

400 jellybeans are about a pound and a pound is 453.592 grams

6 0
3 years ago
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