Answer:
Atoms in the same group share the same amount of valence electrons and reactivity. Atoms in the same period, share energy levels.
Explanation:
Answer:
C₂ = 0.056 ppm
Explanation:
Given data:
Initial volume = 2.0 mL
Initial concentration = 7.0 ppm
Final volume = 250.0 mL
Final concentration = ?
Solution:
Formula:
C₁V₁ = C₂V₂
C₁ = Initial concentration
V₁ = Initial volume
C₂ = Final concentration
V₂ = Final volume
Now we will put the values in formula.
C₁V₁ = C₂V₂
7.0 ppm × 2.0 mL = C₂ × 250.0 mL
C₂ = 14.0 ppm.mL /250.0 mL
C₂ = 0.056 ppm
nitrogen-14, which makes up the vast majority of naturally occurring nitrogen, and nitrogen-15, which is less common.
Answer:
1.46g of PbCrO₄ are the theoretical yield
Explanation:
Theoretical yield is defined as the maximum amount of products that could be produced (Assuming a yield of 100%).
The reaction of Lead (II) nitrate with sodium chromate is:
Pb(NO₃)₂(aq) + Na₂CrO₄(aq) → PbCrO₄(s) + 2NaNO₃ (aq)
First, we need to find molar mass of each reactant in order to determine limiting reactant (As the reaction is 1:1, the reactant with the lower number of moles is the limiting reactant). The moles of the limiting reactant = moles of Lead (II) chromate (The precipitate):
<em>Moles Pb(NO₃)₂ -Molar mass: 331.21g/mol-</em>
1.50g * (1mol / 331.21g) = 4.53x10⁻³ moles Pb(NO₃)₂
<em>Moles Na₂CrO₄ -Molar mass: 161.98g/mol-</em>
1.75g * (1mol / 161.98g) = 0.0108 moles
Pb(NO₃)₂ is limiting reactant and moles of PbCrO₄ are 4.53x10⁻³ moles. The mass is:
4.53x10⁻³ moles PbCrO₄ * (323.19g / mol) =
<h3>1.46g of PbCrO₄ are the theoretical yield</h3>
