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gulaghasi [49]
3 years ago
10

Help please!!!!!!!!!!!!!

Mathematics
1 answer:
svp [43]3 years ago
4 0

Answer:

30 is the perimeter i think 2 x 5 = 10 + 2 x 4.5 = 10 x 2 = 20 so 20 + 10 = 30

I think the area is 45, 5 x 4.5 = 22.5 and 2 x 22.5 = 45

Wait for more responses if needed please.

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Out of every 240 containers of juice brought in a grocery store, 116 are orange juice. what fraction purchased is orange juice
Rzqust [24]
116/240 which simplifies to 29/60 by dividing 116/240 by 4/4.
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4 years ago
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Is Circumference of a circle same as area?​
Klio2033 [76]

Answer:

The circumference of a circle is not the same as the area of the circle because the circumference represents the distance around the circle while the area represents the amount of space within the circle. Hope this helps.

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Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let <em>X</em> = number of vehicles that pass the inspection.

The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

                                    =(0.70)^{3}\\=0.343

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

                                   =1-0.343\\=0.657

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

                         = P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

                              + P (Only 3rd vehicle passes)

                       =(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

                                                       + P (0 vehicles passes)

                                              =0.189+(0.30\times0.30\times0.30)\\=0.216

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0
3 years ago
Which graph represents 2x-5y&lt;15?
disa [49]

Answer:

Step-by-step explanation:

First view 2x-5y<15 as the equation 2x - 5y = 15.  Find the x- and y-intercepts and plot them:  

x-intercept:  let y = 0 and find x:  x = 15/2.  Plot (0, 15/2).

y-intercept:  Let x = 0 and find y:  y = -3.  Plot (0, -3).

Draw a dashed line through these two points.  Shade the area BELOW this line.

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3 years ago
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Supplies for last year cost $1,477, which was $177 over budget. Rounded to the nearest 1%, by what percent did the cost exceed t
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so the cost was 1477, which is 177 over the budget, meaning the budget is 1477 - 177 or just 1300.

now, if we take 1300 to be the 100%, how much in percentage is 177, the overflown amount?

\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 1300&100\\ 177&p \end{array}\implies \cfrac{1300}{177}=\cfrac{100}{p}\implies 1300p=17700\implies p=\cfrac{17700}{1300} \\\\\\ p=\cfrac{177}{13}\implies p\approx 13.62\implies \stackrel{\textit{rounded up}}{p=14}

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3 years ago
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