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MAVERICK [17]
3 years ago
10

Eric invested 5000 dollars in the stock market. The value of his stock increased by 13%. a) what is the amount earned from this

investment?
b) what is the new value of the stock?
Mathematics
1 answer:
blagie [28]3 years ago
4 0

Answer:

Earnings = 650

New\ Value = 5650

Step-by-step explanation:

Given

Amount = 5000

Rate = 13\%

Solving (a): The earnings.

This is calculated as:

Earnings = Amount * Rate

Earnings = 5000 * 13\%

Earnings = 650

Solving (b): New Value

This is calculated as:

So, we have:

New\ Value = Amount + Earnings

New\ Value = 5000 + 650

New\ Value = 5650

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3 years ago
A real world situation for the equation 0.5n=12.5
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Answer:

n=25

Step-by-step explanation:

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7 0
3 years ago
a teacher and 10 students are to be seated along a bench in the bleachers at a basketball game. In how many ways can this be don
Veronika [31]

Wow !

OK.  The line-up on the bench has two "zones" ...

-- One zone, consisting of exactly two people, the teacher and the difficult student.
   Their identities don't change, and their arrangement doesn't change.

-- The other zone, consisting of the other 9 students.
   They can line up in any possible way.

How many ways can you line up 9 students ?

The first one can be any one of 9.   For each of these . . .
The second one can be any one of the remaining 8.  For each of these . . .
The third one can be any one of the remaining 7.  For each of these . . .
The fourth one can be any one of the remaining 6.  For each of these . . .
The fifth one can be any one of the remaining 5.  For each of these . . .
The sixth one can be any one of the remaining 4.  For each of these . . .
The seventh one can be any one of the remaining 3.  For each of these . . .
The eighth one can be either of the remaining 2.  For each of these . . .
The ninth one must be the only one remaining student.

     The total number of possible line-ups is 

               (9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1)  =  9!  =  362,880 .

But wait !  We're not done yet !

For each possible line-up, the teacher and the difficult student can sit

-- On the left end,
-- Between the 1st and 2nd students in the lineup,
-- Between the 2nd and 3rd students in the lineup,
-- Between the 3rd and 4th students in the lineup,
-- Between the 4th and 5th students in the lineup,
-- Between the 5th and 6th students in the lineup,
-- Between the 6th and 7th students in the lineup,
-- Between the 7th and 8th students in the lineup,
-- Between the 8th and 9th students in the lineup,
-- On the right end.

That's 10 different places to put the teacher and the difficult student,
in EACH possible line-up of the other 9 .

So the total total number of ways to do this is

           (362,880) x (10)  =  3,628,800  ways.

If they sit a different way at every game, the class can see a bunch of games
without duplicating their seating arrangement !

4 0
3 years ago
What is the solution to the equation 1/x = x+3/2x^2
Dimas [21]
Hello,

As you write 1/x, x must be different of 0.
\dfrac{1}{x} = \dfrac{x+3}{2x^2} \\

==\textgreater\ 2x^2=x^2+3x \cross`\product \\

==\textgreater\ x^2-3x =0\\

==\textgreater\ x(x-3)=0 \\

==\textgreater\ x=0 (to exclude) or x=3\\

Answer\ x=3



8 0
2 years ago
Read 2 more answers
if 100 aluminum cans weigh 4 pounds and recycling center is paying 25 cents a pound how much will robert be payed for his 330 ca
faust18 [17]
330 x 4 / 100 = 13.2 lbs

<span>4 lbs ------0.25
13.2 lbs ......?

13.2 x 0.25 / 4 = 0.825 = 0.83

answer

83 cents

</span>
7 0
3 years ago
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