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2 years ago

12

What is the greatest possible value for STATS in the cryptarithm shown here given that V = 1? [Different letters represent diffe

rent digits, and no leading digit can equal 0.] ROTOR + LEVEL ----------- STATS

1 answer:

max2010maxim [7]2 years ago

8 0

Answer:

HI!

Step-by-step explanation:

HOLA

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Please help me It's pythagorean theorem

Over [174]

Answer: 4

Step-by-step explanation:

3^2 + b^2 = 5^2

9 + b^2= 25

b^2 = 16

b = ±4

5 0

2 years ago

Read 2 more answers

2x+5= -25 and -3m-6= 40 <br><br> What is the product of x and m?

ivanzaharov [21]

Answer:

Step-by-step explanation:

2x+5= -25 .........(1)

and -3m-6= 40........(2)

Considering (1): 2x+5= -25

2x = -25 - 5

2x = -30

x = -30/2

x = -15

Considering (2): -3m-6= 40

-3m = 40 + 6

-3m = 46

m = -46/3

Product of x and m = (-15) × (-46/3)

= -5 × -46

= 230

4 0

3 years ago

Find the volume of the regular pyramid.

Fofino [41]

Volume
= 1/3 x Area x Height
= 1/3 x 110(Approximately) x 16
≈ 588.8 m^3

Answer is 588.8 m^3.
Hope it helps

7 0

1 year ago

Which pair of functions have the same domain? A. F(x)= sin x and g(x) = tan x B. F(x) = cos x and f(x) = csc x C. G(x) = tan x a

EastWind [94]

Answer:

The correct choice is D

Step-by-step explanation:

The trigonometric functions, $\sin x$ and $\cos x$ are defined for all real numbers.

$\tan x=\frac{\sin x}{\cos (x)}$ , this function is not defined where $\cos x=0$ .

$\cot x=\frac{\cos x}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

$\csc x=\frac{1}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

For option A

The domain of $f(x)=\sin(x)$ is all real numbers.

The domain of g(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

For option B

The domain of $f(x)=\cos(x)$ is all real numbers.

The domain of f(x) =csc(x) is $x\ne n\pi$

For option C,

The domain of G(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

The domain of f(x) =cot(x) is $x\ne n\pi$

For option D;

The domain of f(x) =cot(x) is $x\ne n\pi$

The domain of f(x) =csc(x) is $x\ne n\pi$

3 0

3 years ago

Read 2 more answers

In the 2009 to 2010 school year in country a there were 127,004 in students from country B. This number is 24% more than the num

adoni [48]

If x represents the number of students from country C.

then 122% of x = 116,000

122/100 * x = 116000

Transposing the formula for x;

therefore x = 116000 * 100/122 = 95,082 students

8 0

2 years ago