V=hpir^2
r=2
h=5
pi≈3.141592
v=5*3.141592*2^2
v=5*3.141592*4
v=20*3.141592
v=62.83185307179586476925286766559
round to tenth
62.8 cubic units
The third term is 9
t(3)=2(3)+3
6+3 = 9
Answer: 
Step-by-step explanation:
Sampling distribution of the sample proportion
:

The sampling distribution of the sample proportion
has mean =
and standard deviation =
.
Given : The proportion of left handed people in the population is about 0.10.
i.e. p=0.10
sample size : n= 300
Then , the sampling distribution of the sample proportion
will be :-


(approx)
Hence, the sampling distribution of the sample proportion
is 
Answer:
I've done this before my friend...
She would pay $85.10 in total
74(.15)= 11.1
74+11.1= 85.10