Find the coefficient of x^2 in the expression of (x - 7)^5.
a. -3430
The answer is 7....................................
Answer:
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)
The equation of the given line is
x + 2y = 4
2y = - x + 4
y = -x/2 + 4/2
y = - x/2 + 2
Comparing with the slope intercept form, slope = - 1/2
If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the given line.
Therefore, the slope of the line passing through (- 2, 1) is 2
To determine the intercept, we would substitute m = 2, x = - 2 and y = 1 into y = mx + c. It becomes
1 = 2 × - 2 + c = - 4 + c
c = 1 + 4 = 5
The equation becomes
y = 2x + 5
The value of the product expression (-2x-9y²)(-4x-3) is 8x² + 6x + 27y² + 36xy²
<h3>How to evaluate the product?</h3>
The expression is given as:
(-2x-9y²)(-4x-3)
Expand the expression
8x² + 6x + 27y² + 36xy²
Hence, the value of the product expression (-2x-9y²)(-4x-3) is 8x² + 6x + 27y² + 36xy²
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Answer:ed
Step-by-step explanation:
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