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Rufina [12.5K]
2 years ago
12

There is a bag of marbles that contains 4 blue marbles, 3 red marbles, 2 green marbles, and 1 brown marble. If one was picked at

random, not replaced, and another was picked, what is the probability of both marbles selected to be blue?
Mathematics
1 answer:
Anika [276]2 years ago
6 0

Answer:

2/15

Step-by-step explanation:

4/10 * 3/9 = 12/90 = 2/15

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Find the area; reduce to lowest terms:
tamaranim1 [39]
Area = length x width

area = 2 3/4 x 2/5

area = 1 1/10 feet :)
5 0
2 years ago
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in Hanley's school, 0.723 of the students participated in an event. if there are 1000 students in Hanley School, how many partic
Ugo [173]
Answer:

723 students participated in the event

Explanations:

The total number of students in Hanley's school = 1000

0.723 of the students participated in an event

Number of students that participated in the event = 0.723 x 1000

Number of students that participated in the event = 723

4 0
1 year ago
National data indicates that​ 35% of households own a desktop computer. In a random sample of 570​ households, 40% owned a deskt
Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a​ desktop.

Step-by-step explanation:

We are given that National data indicates that​ 35% of households own a desktop computer.

In a random sample of 570​ households, 40% owned a desktop computer.

<em><u>Let p = population proportion of households who own a desktop computer</u></em>

SO, Null Hypothesis, H_0 : p = 25%   {means that 35% of households own a desktop computer}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 570​ households who owned a desktop computer = 40%

            n = sample of households = 570

So, <u><em>test statistics</em></u>  =  \frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }

                               =  2.437

<em>Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.</em>

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0
2 years ago
Percent error Please Help
san4es73 [151]

Answer:

2%

Step-by-step explanation:

Set up the problem with the numbers given to you

\frac{13.3 - 13.6}{13.6} x 100

-0.022058823529412 x 100

-2.205882352941176

Don't forget that it's absolute value and that you round to the nearest percent

2%

5 0
3 years ago
Six added to 3 times a number is equal to 4 less than 5 times the number. What is the number?
harina [27]

Answer:

5

Step-by-step explanation:

Let the number be x.

3x+6=5x-4

3x-5x=-4-6

-2x=-10

2x=10

2x/2=10/2

x=5

The number is 5.

8 0
2 years ago
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