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Nadya [2.5K]
3 years ago
11

Please need help ASAP 15 points????I need a,b,c

Physics
2 answers:
Anettt [7]3 years ago
6 0

Answer:

The acceleration is negative and very close to zero.

Very Small, because it slowly comes to a stop, which means there is nothing to stop it any faster

It would keep traveling in that direction without slowing down

Explanation:

Ronch [10]3 years ago
4 0

Answer:

A,B,C

Explanation:

A) because the ball is slowing down that means that the acceleration is changing and is slowing. It also means that it has negative acceleration because it is going the opposite way of velocity. When it stops then there is no more acceleration

B) Net force is calculated by the sum of the forces that are acting on the object. If the net force is unbalanced then it will speed up, slow down, or change direction. So basically, net force is an unopposed force that causes a change in motion. First, it has a net force because it's moving and is not in equilibrium. Second, the net force would be changing as it is stopping. When it stops then it would be in static equilibrium. Basically, the net force is changing as the speed slows down until it comes to a state of equilibrium.

C) If it was in space then it would never stop. Because of the law of inertia, an object in motion will stay in motion as long as there are no other opposing forces. Because there really aren't opposing forces in space, it would keep on going forever.

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Explanation:

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3 years ago
I need help quick!
zvonat [6]

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Explanation:

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3 years ago
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polet [3.4K]

(C) 200 N

Explanation:

The acceleration due to gravity on earth g_{E} is given by

g_{E} = G\dfrac{M_{E}}{R_{E}^{2}}

where G = universal gravitational constant

\:\:\:\:\:\:\:\:\:\:\:\:M_{R} = mass of the earth

\:\:\:\:\:\:\:\:\:\:\:\:R_{E} = radius of the earth

Planet Krypton has twice the mass of earth and 3 times the radius so its acceleration due to gravity g_{K} is

g_{K} = G\dfrac{M_{K}}{R_{K}^{2}}

\:\:\:\:\:\: = G\dfrac{(2M_{E})}{(3R_{E})^{2}}

\:\:\:\:\;\:= (\dfrac{2}{9})G\dfrac{M_{E}}{R_{E}^{2}}

or

g_{K} = (\dfrac{2}{9})\:g_{E}

If we multiply both sides by Superman's mass, we get his weights on both planets:

mg_{K} = (\dfrac{2}{9})\:(mg_{E})

W_{K} = (\dfrac{2}{9})\:W_{E} = (\dfrac{2}{9})(900\:N)= 200\:N

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