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3 years ago

Table A: Calculation of Density for Regularly Shaped Solids

Physics

1 answer:

kramer3 years ago

4 0

Explanation:

Table A: Calculation of Density for Regularly Shaped Solids

Table tennis ball Golf ball

"Mass

(g)"

Diameter (cm)

Radius (cm)

Estimated volume (cm3)

Estimated density (g/cm3)

"Prediction of buoyancy

Circle one."

"Observation of buoyancy

Circle one."

Initial volume of water (cm3)

Final volume of water (cm3)

Change in volume (cm3)

Calculated density (g/cm3)

Error (%)

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Answer:

Approximately $1.6\times 10^{3}\; \rm N$ .

Explanation:

By the Impulse-Momentum Theorem, the change in this woman's momentum will be equal to the impulse that is applied to her.

The momentum $p$ of an object is equal to the product of its mass $m$ and velocity $v$ . That is: $p = m \cdot v$ .

Let $v(\text{before})$ and $v(\text{after})$ represent the velocity of the woman before and after the landing. Let $m$ represent the woman's mass.

The woman's momentum before the landing would be $m \cdot v(\text{before})$ .
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Therefore, the change in this woman's momentum would be:

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On the other hand, impulse is equal to force multiplied by the duration of the force. Let $F$ represent the average force on the woman. The impulse on her during the landing would be $F \cdot t$ .

Apply the Impulse-Momentum Theorem.

Impulse: $F\cdot t$ .
Change in momentum: $m \cdot (v(\text{after})- v(\text{before}))$ .

Impulse is equal to the change in momentum:

$F \cdot t = m \cdot (v(\text{after})- v(\text{before}))$ .

After landing, the woman comes to a stop. Her velocity would become zero. Therefore, $v(\text{after}) = 0\; \rm m \cdot s^{-1}$ .

$\begin{aligned}F &= \displaystyle \frac{m \cdot (v(\text{after})- v(\text{before}))}{t} \\ &= \frac{50.5\; \text{kg} \times \left(0 \; \mathrm{m \cdot s^{-1}}- 8.4\; \mathrm{m \cdot s^{-1}}\right)}{0.27\; \rm s} \\ &\approx 1.6 \times 10^{3}\; \rm N\end{aligned}$ .

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I just took the test and it was right :D

The correct answer is B.

I hope this helped! :D

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