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3 years ago

What is silicone used for

2 answers:

8 0

It can be used with seatbelts , Adhesives, lubricants, machine, cooking utensils, the thermal and electrical installation. Some common forms include silicon oil silicon grease silicone rubber silicone relish in silicone caulk.

enot [183]3 years ago

6 0

Answer:

sealants, adhesives, lubricants, medicine, cooking utensils, and thermal and electrical insulation

Explanation:

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A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what wil

Ludmilka [50]

Answer:

Volume : 1.25 L

Explanation:

We are given here that the volume ( V $_1$ ) = 1.50 Liters, the initial moles ( held at 25 °C ) = 3.00 mol, and the final moles ( n $_2$ ) = 3.00 - 0.5 = 2.5 mol. The final mol is calculated given that 0.50 mol of gas are released from the prior 3.00 moles of gas.

Volume ( V $_1$ ) = 1.50 L,

Initial moles ( n $_1$ ) = 3.00 mol,

Final Volume ( n $_2$ ) = 3.00 - 0.5 = 2.5 mol

Applying the combined gas law, we can calculate the final volume ( V $_2$ ).

P $_1$ V $_1$ / n $_1$ T $_1$ = P $_2$ V $_2$ / n $_2$ T $_2$ - we know that the pressure and temperature are constant, and therefore we can apply the following formula,

V $_1$ / n $_1$ = V $_2$ / n $_2$ - isolate V $_2$ ,

V $_2$ = V $_1$ n $_2$ / n $_1$ = 1.50 L $*$ 2.5 mol / 3.00 mol = ( 1.5 $*$ 2.5 / 3 ) L = 1.25 L

The volume of the balloon will be 1.25 L.

6 0

3 years ago

When 4.5 mol al react with 11.5 mol hcl, what is the limiting reactant, and how many moles of h2 can be formed?

ahrayia [7]

1°/ . 2 Al + 6 HCl → 2 AlCl3 + 3 H2

k1 = n(Al) / 2 = 4,5 / 2 = 2,25 
k2 = n(HCl) / 6 = 11,5 / 6= 1,92 

k2 < k1 ==> HCl is the limiting reactant 

6 mol of HCl ---> 2 mol of H2 
11,5 mol of HCl ---> 3,83 mol of H2

5 0

3 years ago

This electron cloud model of aluminum has _______ energy levels with _______ electrons on its outer energy level. A) 1, 2 B) 2,

Talja [164]

Answer:

Explanation:

Have anice day

7 0

3 years ago

A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain

sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

$-w=\frac{dm}{dt}$

w is the mass flow

m is the mass of salt

$-v*C=\frac{dm}{dt}$

v is the volume flow

C is the concentration

$C=\frac{m}{V+(6-3)*L/min*t}$

$-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}$

$-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}$

$-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)$

$-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)$

$m=90kg*[2000L/(2000L+3*L/min*t)]$

a) Initially: t=0

$m=90kg*[2000L/(2000L+3*L/min*0)]=90kg$

b) t=210 min (3.5 hr)

$m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg$

c) If time trends to infinity the division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

6 0

3 years ago

Which substance is the reducing agent in this reaction? 2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH

LuckyWell [14K]

2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH
In a reaction, the reducing agent is the element or compound that donates electron or the one tht loses electrons. The oxidized species. The opposite is called the oxidizing agent. It is the one who accepts the electrons lost. For this reaction KMnO4 is reduced into MnO2.

5 0

3 years ago

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