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2 years ago

Griffin made the following list of the different outer coverings of a plant. which part of his list is incorrect?

Chemistry

1 answer:

liraira [26]2 years ago

5 0

Stamen is not an outer covering its the reproductive organ of the plants.

<h3>What is use of covering of Plants ?</h3>

Outer covering of plants is useful in protecting them from environment factors , it is useful in keeping the moisture intact inside the plants.

Among the different outer covering , Bark ,stamen , spines and fuzzy hairs

Bark , stamen and fuzzy hairs are all the outer covering of plants

Stamen is not an outer covering its the reproductive organ of the plants.

To know more about outer covering of Plants

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An object has a density of 40 g/cm3 and a mass of 240 g what is it’s volume

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Answer:

6cm^3

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6 cm^3

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3 years ago

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4 years ago

Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide:You add 40.7 g of M

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: 4 HCl + MnO2 → MnCl2 + 2 H2O + Cl2

(33.7 g MnO2) / (86.93691 g MnO2/mol) = 0.38764 mol MnO2
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(a)
1.2424 moles of HCl would react completely with 1.2424 x (1/4) = 0.3106 mole of MnO2, but there is more MnO2 present than that, so MnO2 is in excess and HCl is the limiting reactant.

(b)
(1.2424 mol HCl) x (1 mol Cl2 / 4 mol HCl) x (70.9064 g Cl2/mol) = 22.0 g Cl2

(c)
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5 0

3 years ago

Answer both 8 and 9 will give u brain list with explanation as well so don’t just answer

goldfiish [28.3K]

Answer:

8. the answer is B.

9. the answer is A.

Explanation:

Hello!

8. In this case, by bearing to mind that the limiting reactant is always completely consumed and the excess one remain as a leftover at the end of the reaction, we can also infer that as all the limiting reactant is consumed, it must determine the maximum amount of product as the excess reactant will hypothetically produce a greater mass than expected; thus, the answer to this question is B.

9. In this case, since the mole ratio of oxygen to water is 1:2, the following proportional factor is used to calculate the produced mass of water:

$3molO_2*\frac{2molH_2O}{1molO_2}=6molH_2O$

Thus, the answer is this case is A.

Best regards!

6 0

3 years ago