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timama [110]
3 years ago
5

Using the following reaction:

Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0

Answer:

Mn is the oxidizing agent.

N is the reducing agent.

Explanation:

Hello!

In this case, according to the undergoing chemical reaction, it is seen that the manganese in KMnO4 has an oxidation state of 7+, in MnSO4 of 2+ and nitrogen in KNO2 is 3+ and in KNO3 is 5+; thus we have the following half-reactions:

Mn^{7+}+5e^-\rightarrow Mn^{2+}\\\\N^{3+}\rightarrow N^{5+}+2e^-

Thus, since manganese is undergoing a decrease in the oxidation state, we infer it is the oxidizing agent whereas nitrogen, undergoing an increase in the oxidation state is the reducing agent.

Best regards!

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4 0
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Reaction is
-Dominant- [34]
According  to the task, you  are proveded with patial pressure of CO2 and graphite, and here is complete solution for the task :
At first you have to find n1 =moles of CO2 and n2 which are moles of C 
<span>The you go :
</span>CO2(g) + C(s) \ \textless \ =\ \textgreater \  2CO(g)

n1 n2 0
-x -x +2x
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After that you have to use the formula PV=nRT
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Then you have to solve x, and for that you have to use <span>RT/V
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I am absolutely sure that this would be helpful for you.
7 0
3 years ago
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