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timama [110]
2 years ago
5

Using the following reaction:

Chemistry
1 answer:
Romashka-Z-Leto [24]2 years ago
5 0

Answer:

Mn is the oxidizing agent.

N is the reducing agent.

Explanation:

Hello!

In this case, according to the undergoing chemical reaction, it is seen that the manganese in KMnO4 has an oxidation state of 7+, in MnSO4 of 2+ and nitrogen in KNO2 is 3+ and in KNO3 is 5+; thus we have the following half-reactions:

Mn^{7+}+5e^-\rightarrow Mn^{2+}\\\\N^{3+}\rightarrow N^{5+}+2e^-

Thus, since manganese is undergoing a decrease in the oxidation state, we infer it is the oxidizing agent whereas nitrogen, undergoing an increase in the oxidation state is the reducing agent.

Best regards!

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How much sucrose (g) do you need to weight in order to prepare 19.16 g of a 13.1 % (weight percent) solution?
Nonamiya [84]
<span>2.51 grams
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3 0
3 years ago
a water sample is found to have a cl- content of 100ppm as nacl what is the concentration of chloride in moles per liter
ladessa [460]

Answer:

The concentration of chloride ion is 2.82\times10^{-3}\;mol/L

Explanation:

We know that 1 ppm is equal to 1 mg/L.

So, the Cl^- content 100 ppm suggests the presence of 100 mg of Cl^- in 1 L of solution.

The molar mass of Cl^- is equal to the molar mass of Cl atom as the mass of the excess electron in Cl^- is negligible as compared to the mass of Cl atom.

So, the molar mass of Cl^- is 35.453 g/mol.

Number of moles = (Mass)/(Molar mass)

Hence, the number of moles (N) of Cl^- present in 100 mg (0.100 g) of Cl^- is calculated as shown below:

N=\frac{0.100\;g}{35.453\;g/mol}=2.82\times 10^{-3}\;mol

So, there is 2.82\times10^{-3}\;mol of Cl^- present in 1 L of solution.

5 0
3 years ago
The following balanced equation shows the formation of water. 2H2 + O2 2H2O How many moles of oxygen (O2) are required to comple
motikmotik

Answer:

13.7 moles of O₂ are needed

Explanation:

In order to find the moles of reactants that may react to make the products we need to determine the reaction:

Reactants are hydrogen and oxygen

Product: Water

2 moles of hydrogen can react to 1 mol of oxygen and produce 2 moles of water.

Balanced reaction: 2H₂(g) + O₂(g) →  2H₂O(l)

If 2 moles of hydrogen need 1 mol of oxygen to react

Therefore, 27.4 moles of H₂ must need (27.4 .1) / 2 = 13.7 moles of O₂

8 0
2 years ago
HELP PLEASE !!!! DUE NOW!!
ratelena [41]

Answer:

The ratio of the products to reactants remains caonstant over time

Explanation:

6 0
3 years ago
Calculate the vapor pressure of a solution made by dissolving 109 grams of glucose (molar mass = 180.2 g/mol in 920.0 ml of wate
Fynjy0 [20]
Given data: <span>molar mass = 180.2 g/mol in 920.0 ml of water at 25 °c.
                   </span><span>the vapor pressure of pure water at 25 °c is 23.76 mm hg. 
</span>Asked: <span>the vapor pressure of a solution made by dissolving 109 grams of glucose
</span><span>
Solution:
moles glucose = 109 g/ 180.2 g/mol=0.605 
mass water = 920 mL x 1 g/mL = 920 g 
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mole fraction water = 51.1 / 51.1 + 0.605 =0.988 
vapor pressure solution = 0.988 x 23.76 = 23.47 mm Hg</span>
6 0
3 years ago
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