Answer:
![\boxed {\boxed {\sf 250 \ people}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20250%20%5C%20people%7D%7D)
Step-by-step explanation:
Let's set up a proportion using the following setup.
![\frac {buses}{people}=\frac {buses}{people}](https://tex.z-dn.net/?f=%5Cfrac%20%7Bbuses%7D%7Bpeople%7D%3D%5Cfrac%20%7Bbuses%7D%7Bpeople%7D)
We know 30 buses can carry 1,500 people.
![\frac {30 \ buses}{1500 \ people}=\frac {buses}{people}](https://tex.z-dn.net/?f=%5Cfrac%20%7B30%20%5C%20buses%7D%7B1500%20%5C%20people%7D%3D%5Cfrac%20%7Bbuses%7D%7Bpeople%7D)
We don't know how many people 5 buses can carry, so we say 5 buses carry x people.
![\frac {30 \ buses}{1500 \ people}=\frac {5 \ buses}{x \ people}](https://tex.z-dn.net/?f=%5Cfrac%20%7B30%20%5C%20buses%7D%7B1500%20%5C%20people%7D%3D%5Cfrac%20%7B5%20%5C%20buses%7D%7Bx%20%5C%20people%7D)
![\frac {30 }{1500 }=\frac {5 }{x }](https://tex.z-dn.net/?f=%5Cfrac%20%7B30%20%7D%7B1500%20%7D%3D%5Cfrac%20%7B5%20%7D%7Bx%20%7D)
Cross multiply. Multiply the numerator of the first fraction by the second fraction's denominator. Then, multiply the first denominator by the second numerator.
![30*x=1500*5\\30x=7500](https://tex.z-dn.net/?f=30%2Ax%3D1500%2A5%5C%5C30x%3D7500)
Solve for x. It is being multiplied by 30. The inverse of multiplication is division. Divide both sides by 30.
![30x/30=7500\\x=250](https://tex.z-dn.net/?f=30x%2F30%3D7500%5C%5Cx%3D250)
5 buses can carry 250 people.
Answer:
$12
Step-by-step explanation:
assuming that the cost of delivery is constant irrespective of the number ordered
Let the cost of sandwich be x
First office
$33=4x+c where c is the cost of delivery
Second office
$61=8x+c
These two are simultaneous equation. Subtracting the equation of first office from the second office we obtain
4x=28
Therefore, x=28/4=7
The cost of delivery is 33-(4*7)=33-28=5
Therefore, one sandwich plus delivery costs 7+5=$12
Answer:
y=3x+1=4
y=5x-1=4
Step-by-step explanation:
DO THE MATH
Answer:
48
Step-by-step explanation:
base times hight times times 1/2
24X4X1/2
Step-by-step explanation:
S = { 1, 2, 3, 4, 5, 6 7, 8 }
n ( S ) = 8
Let A be the event of getting 4,
A = { 4 }
n ( A ) = 1
P ( A )
= n ( A ) / n ( S )
= 1 / 8
Therefore, the probability of spinning a 4 is 1 / 8.
S = { A, B, A, C, A, B }
n ( S ) = 6
Let Y be the event of getting C,
Y = { C }
n ( Y ) = 1
P ( Y )
= n ( Y ) / n ( S )
= 1 / 6
Therefore, the probability of spinning a C is 1 / 6.