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lisov135 [29]
3 years ago
11

12. What assumption might you be tempted to make about the graphs of y = x, y = x3 and y = x5 based on the values you found in t

he 3 tables above?​
Mathematics
1 answer:
ohaa [14]3 years ago
8 0

Answer:

Sorry need the cred

Step-by-step explanation:

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Can somebody Help me please?!
antoniya [11.8K]
The first one because if you add all the positives you get 4 and then if you add all the negatives you get 7 so then you do 4+(-7)= -3
6 0
3 years ago
Please help
asambeis [7]

Answer:

A, of money in the account after 3 years subject to interest ... If you deposit P dollars at rate r, in decimal form, subject to compound interest paid

Step-by-step explanation:

4 0
3 years ago
HEY GUYS I NEED HELP WITH THIS PLZZ! write down everything from the detail of how yall found ur answer plzz! 20 points or more..
aleksley [76]

Answer:

1/6+1/8+$13.50+$5=x

x=$18.79

Step-by-step explanation:

i add them

first i find the common denominator for 1/6 and 1/8

then i add 13.50 by 5

then add 18.50 by 7/24

i hope this explains how i got my answer

5 0
4 years ago
Read 2 more answers
Lim x-->0 ((sqrt(ax+b) -2) / x) =1 show steps....
Andrew [12]
Lim x→0 (√(ax+b)-2)/x=1

You want to know the value of "a" and "b"

lim x→0  (√(ax+b)-2)/x=(√(0+b)-2)/0=(√b -2)/0;

Then if (√b -2)/0=1; the numerator must be "0"
(√b-2)=0
√b=2
(√b)²=2²
b=4

It is necessary the numerator must be "0", if the denominator is "0" and the result is equal a number.

Therefore:
lim     (√(ax+4)-2)/x=1
x⇒0

I imagine you know Taylor Series.
√(ax+4)=(4(1+ax/4))¹/²=2(1+ax/4)¹/²
Remember:
               (1/2)   
(1+x)ᵃ=<span>Σ ( a  ) x^a
</span>
In our case:
                   (1/2)             (1/2)              (1/2)
(1+ax/4)¹/²=(   0) (ax/4)⁰+(  1 ) (ax/4)¹+(   2) (ax/4)²+...
                =1 +(1/2) ax/4 + -1/8 (ax/4)²+...
                =1+ax/8-a²x²/128+...

Therefore:
lim     (√(ax+4)-2)/x=lim       [2(1+ax/8-a²x²/128+...)-2]/x=
x⇒0                          x⇒0 

lim       [(2+ax/4-a²x²/64+...)-2]/x=
x⇒0 

lim      (ax/4-a²x²/64+...)/x=
x⇒0

lim   x(a/4-a²x/64+...)/x=
x⇒0

lim    (a/4-a²x/64+...)=(a/4-0-0-0-...)=4/a
x⇒0

Because:

lim     (√(ax+4)-2)/x=1
x⇒0

Then:
4/a=1 ⇒  a=4

Answer: a=4; b=4
4 0
3 years ago
What is the domain of the graphed function?
postnew [5]

Answer:

y 1 X (a)y=X2—1 y —l 0 l x <b>y= |x2—1| FIGURE |0 x (input) f(g(x)) (output) FIG ... FROM OLD FUNCTIONS 4| I] EXAMPLE 5 Sketch the graph of the function y = |x2 ... a manner similar to the way we add, subtract, multiply, and divide real numbers. ... but we can't divide by O and so the domain of fly is {x E A O B| g(x) 75 O}.

Step-by-step explanation:

7 0
3 years ago
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