F(n)=3n
f(1/3)=3(1/3)
f(1/3)=1
Hope I didn't mess up for your sake
The interval where the function is increasing is (3, ∞)
<h3>Interval of a function</h3>
Given the rational function shown below
g(x) = ∛x-3
For the function to be a positive function, the value in the square root must be positive such that;
x - 3 = 0
Add 3 to both sides
x = 0 + 3
x = 3
Hence the interval where the function is increasing is (3, ∞)
Learn more on increasing function here: brainly.com/question/1503051
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Answer:
-2.43655
Step-by-step explanation:
Scientific notation is a way to write compactly numbers with lots of digits, either because they're very large (like 2393490000000000000000000), or very small (like 0.0000000000356).
We use powers of ten to describe all those leading/trailing zeros, so that we con concentrate on the significat digits alone.
In your case, the "important" part of the number is composed by the digits 6 and 1, all the other digits are zero. But how many zeroes? Well, let's do the computation.
Every power of 10, 
is written as one zero followed by n zeroes, so we have
Multiplying a number by means to shift the decimal point to the right and/or add trailing zeroes n times. So, we have to repeat this process six times. We shift the decimal point to the right one position, and then add the five remaning zeroes. The result is thus
