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The molar mass of the product is equal to 62g/mol.
<h3>Mole calculation</h3>
To calculate the molar mass of a compound it is necessary to have knowledge of the atomic mass of all the elements involved.
In the case of the question, we have the reaction between flourine and magnesium, which represents the element of group 2 with the presented electronic configuration.
Thus, we have the following reaction:

So, just add the molar masses, having:


So, the molar mass of the product, round to the nearest tenth, is equal to 62g/mol.
Learn more about mole calculation in: brainly.com/question/2845237
Answer:
Group B
Explanation:
The control group of an experiment is considered to be the "normal" because it does not receive the expeiemental treatment and hence is used to compare with the experimental group. The control and experimental groups are similar in every other aspect with the exception of the "INDEPENDENT VARIABLE". The independent variable is not changed in the control group.
In this experiment, the control group is GROUP B, which was given a plain gatorade without adding sugar. Sugar is the independent variable here, and it was not included in GROUP B, meaning that GROUP B is the CONTROL GROUP. On the other hand, the experimental group is the GROUP A.
Answer:






Explanation:
In the first nucleus we are told that there are two protons and one neutron. Let us remember that the mass number = number of protons + number of neutrons.
This implies that, for the first specie the mass number is 3, for the second specie the mass number is 6 and the third specie has a mass number of 7 and so on. The mass number is indicated as a superscript.
The atomic number is the number of protons in the nucleus of the atom and helps us to identify the atom. It is always written as a subscript as shown.
Given
Mass of NO - 824 g
Molar mass of NO - 30.01g/mol
No of moles of NO = Given mass/Molar mass
No of moles of NO = 824/30.01= 27.45 mole
Hence 27.5 moles of NO are formed!