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kobusy [5.1K]
3 years ago
15

What is the cientific result for making marshmellows?

Chemistry
1 answer:
natta225 [31]3 years ago
8 0

the result is a mix of sticky and yummy


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Forces that act between two molecules are referred to as intermolecular forces true or false
julsineya [31]
Answer:
            TRUE: <span>Forces that act between two molecules are referred to as Intermolecular Forces.

Explanation:
                   Those forces which are present within the molecule among atoms are called as Intramolecular Forces, while, The forces which are present between two molecules are called as Intermolecular Forces. Intermolecular Forces are as follow,

                1) Hydrogen Bond Interactions

                2) Dipole-Dipole Interactions

                3) London Dispersion Forces</span>
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3 years ago
Name 2 ways forelimbs are different than hind limbs.
Allisa [31]
<span>Hind limbs will typically be stronger than forelimbs. For some animals this is because they are used for self-defense (a horse or donkey kicking, for example). Forelimbs are not going to be as strong and are often used for feeding oneself, and not intended to be as weight bearing in many mammals.</span>
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3 years ago
Which term describes matter that is a substance made of diffrent kinds of atoms bonded together
Alex777 [14]
Compounds are substances made of at least 2 different elements. Molecules have at least 2 atoms, doesn't have to be different elements. Compounds and molecules both work.
8 0
3 years ago
Why can hydrogen only form one covalent bond?
MrRa [10]
Because its in group one....which only lose or gain electrons.....thus it will only have oneelectron to fulfill its octect rule
7 0
2 years ago
hat is the pressure of CO(g) in equilibrium with the CO2(g) and O2(g) in the atmosphere at 25 ????C? The partial pressure of O2(
Lubov Fominskaja [6]

Answer:

The partial pressure of CO is 5.54x10⁻⁴⁹atm. You shouldn't worry because it is very low pressure

Explanation:

First, the balanced reaction is:

CO + 1/2O₂ → CO₂

The energies of formation are:

ΔG(CO)=-137.168kJ/mol

ΔG(O₂)=0

ΔG(CO₂)=-394.359kJ/mol

The energy of the reaction is:

delta-G_{reaction} =delta-G_{CO_{2} } -(delta-G_{CO} +1/2delta-G_{O_{2} } )\\delta-G_{reaction}=-394.359-(-137.168+0)=-257.191kJ/mol

The expression for calculate the partial pressure of CO is:

p_{CO} =\frac{p_{CO2} }{p_{O_{2} }^{1/2}*exp^{-\frac{delta-G}{RT} }   } \\p_{CO}=\frac{3x10^{-4} }{0.2^{1/2}*exp(-\frac{-257.191*1000}{8.314*298} ) } \\p_{CO}=5.54x10^{-49} atm

5 0
3 years ago
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