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Effectus [21]
3 years ago
14

A solution that contains a small amount of salt and a large amount of water is said to be a ____________ solution.

Chemistry
2 answers:
sergij07 [2.7K]3 years ago
8 0
Ello love the answer is c
Have a nice day love
BARSIC [14]3 years ago
3 0
A. saturated
hope this helped ya
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At a temperature of 280 K, the gas in a cylinder has a volume of 20.0 liters. If the volume of the gas is decreased to 10.0 lite
seraphim [82]

To solve this we assume that the gas inside is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

T1 / V1 = T2 / V2

 

T2 = T1 x V2 / V1

 

T2 = 280 x 20.0 / 10

 

<span>T2 = 560 K</span>

8 0
3 years ago
Read 2 more answers
WHO CAN HELP ME ON THIS NEED OF HELP! Due soon !
Otrada [13]

Answer:

Runoff from a cattle ranch

7 0
2 years ago
1. Marisa determined the melting point of a substance to be 24.5C. Find the percent error of her measurement if the actual melti
USPshnik [31]

Answer:

\%\ Error = 21.5\%

Explanation:

Given

Measured = 24.5

Actual = 31.2

Required

Determine the percentage error

First, we need to determine the difference in the measurement

Difference = |Actual - Measured|

Difference = |31.2 - 24.5|

Difference = |6.7|

Difference = 6.7

The percentage error is calculated as thus:

\%\ Error = \frac{Difference * 100\%}{Actual}

\%\ Error = \frac{6.7 * 100\%}{31.2}

\%\ Error = \frac{670\%}{31.2}

\%\ Error = 21.4743589744\%

\%\ Error = 21.5\% <em>approximated</em>

6 0
3 years ago
Instructions:Select the correct answer.
andriy [413]
Activity series of metals: K,Na,Mg,Al,Zn,Fe,Cu,Ag. Metals on the left are more reactive than metals on the right. For example Zn is more reactive than Fe and can displace him. 
Reaction than can occur is: <span>CuSO4(aq) + Fe(s) → FeSO4(aq) + Cu(s).</span>
8 0
3 years ago
A 25.0g tin sample was placed in boiling water at 99.5 C until it had the same temperature. Afterwards, the tin sample was place
MrMuchimi

Answer : The specific heat of tin is, 0.213 J/g.K

Explanation :

Formula used :

q=m\times c\times (T_{final}-T_{initial})

where,

q = amount of heat lost = -399.4 J

c = specific heat capacity of tin = ?

m = mass of tin = 25.0 g

T_{final} = final temperature = 24.5^oC=273+24.5=297.5K

T_{initial} = initial temperature = 99.5^oC=273+99.5=372.5K

Now put all the given values in the above formula, we get:

-399.4J=25.0g\times c\times (297.5-372.5)K

c=0.213J/g.K

Therefore, the specific heat of tin is, 0.213 J/g.K

7 0
3 years ago
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