600Hz is the driving frequency needed to create a standing wave with five equal segments.
To find the answer, we have to know about the fundamental frequency.
<h3>How to find the driving frequency?</h3>
- The following expression can be used to relate the fundamental frequency to the driving frequency;
f(n) = n * f (1)
where, f(1) denotes the fundamental frequency and the driving frequency f(n).
- The standing wave has four equal segments, hence with n=4 and f(n)=4, we may calculate the fundamental frequency.
f(4) = 4× f (1)
480 = 4× f(1)
f(1) = 480/4 =120Hz.
So, 120Hz is the fundamental frequency.
- To determine the driving frequency necessary to create a standing wave with five equally spaced peaks?
- For, n = 5,
f(n) = n 120Hz,
f(5) = 5×120Hz=600Hz.
Consequently, 600Hz is the driving frequency needed to create a standing wave with five equal segments.
Learn more about the fundamental frequency here:
brainly.com/question/2288944
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<em>The correct option is </em><em>A</em>. The information we know about the known exoplanets is estimates of orbits and masses.
<h3>What is exoplanets?</h3>
An exoplanet or extrasolar planet is a planet outside the Solar System.
In other words, exoplanet is any planet beyond our solar system.
<h3>Characteristics of exoplanets</h3>
exoplanets are known for the following characteristics;
- they are usually hot
- they can orbit their stars so tightly that a “year” lasts only a few days
- they can orbit two suns at once
Thus, the information we know about the known exoplanets is estimates of orbits and masses.
Learn more about exoplanets here: brainly.com/question/1514493
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Johann Strauss II
hope this helps
Answer:
73.72
Explanation:
For this subtraction problem, the answer or solution is expressed to the least precise of the numbers we are trying to subtract.
The least precise number is the number with the lowest significant numbers:
105.4 - 31.681
105.4 has 4 significant numbers
31.681 has 5 significant numbers
So;
105.4
- 31.681
------------------
73.719
----------------
The solution is therefore 73.72
Answer:
Solution given:
frequency[f]=60,500,000Hz
velocity[V]=300,000,000m/s
wave length=?
we have
wave length=
=
=
=4.96 m
Option A.4.96m