Answer:

Explanation:
Given:
density, 
diameter of the pipe, 
pressure difference, 
In case of pitot tube, the velocity is given by:



Now we know that volumetric flow rate is given as:

where :
a= cross sectional area of the pipe
v= velocity of flow


The accurate answer is
The psychiatrist that <span>believed the environment was more important to a child's intellectual development than biology was "D" </span>Sigmund Freud.
Current(I) = Voltage/Resistance
= 42/(10+ 4)
= 42/14
Current = 3 A
Answer:
Kelvin to Celsius: C = K - 273 (C = K - 273.15 if you want to
The electric potential energy of the pair of charges when the second charge is at point b is U at b = +7.3×10⁻⁸J.
Electric potential is the amount of work done in moving point charge from infinity to aspecific point.
Calculation of the electric potential energy:
Here the particle should be moved from the point at the time when the potential energy should be U a
The U b should be the change in the potential energy
W is work done.
(W at a )-(W at b) = U a - U b
U b = U a - (W at a )+(W at b)
So,
= 5.4 × 10⁻⁸J - ( -1.9×10⁻⁸ J)
= +7.3×10⁻⁸J.
Learn more about electric potential here:
brainly.com/question/24284560
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