What are the two consecutive integers of 134?
2 answers:
You might be interested in
Hi there!
To find the indefinite integral, we must integrate by parts.
Let "u" be the expression most easily differentiated, and "dv" the remaining expression. Take the derivative of "u" and the integral of "dv":
u = 4x
du = 4
dv = cos(2 - 3x)
v = 1/3sin(2 - 3x)
Write into the format:
∫udv = uv - ∫vdu
Thus, utilize the solved for expressions above:
4x · (-1/3sin(2 - 3x)) -∫ 4(1/3sin(2 - 3x))dx
Simplify:
-4x/3 sin(2 - 3x) - ∫ 4/3sin(2 - 3x)dx
Integrate the integral:
∫4/3(sin(2 - 3x)dx
u = 2 - 3x
du = -3dx ⇒ -1/3du = dx
-1/3∫ 4/3(sin(2 - 3x)dx ⇒ -4/9cos(2 - 3x) + C
Combine:
Answer:
Option B. t=5/3w ;1/3
Step-by-step explanation:
We are told that varies Inversely with
thus generally speaking
∝
since they are inverted, <u>otherwise</u> if they were proportionally varied then
∝
. This means that there is a constant value (
) for which
is inversely proportional to
and can be mathematically expressed as:
Eqn. (1)
Now since we are given the values of and
, we can plug them in Eqn. (1) and find our constant of proportionality
as follow:
Now that we have our constant we can find the new value for the second value of
as follow:
Therefore based on the options give, we can see that Option B. is correct since
and for
, then