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Oksanka [162]
2 years ago
10

What are the two consecutive integers of 134?

Mathematics
2 answers:
Dmitry_Shevchenko [17]2 years ago
7 0

Answer:

The integers are 66 and 68.

Step-by-step explanation:

Let the two consecutive integers be 2n and 2n+2

Therefore we can write

2n+2n+2=134

or

4n=134−2

or

4n=132

or

n=132/4

or

n=33

Therefore the integers are

By putting the value of n:

2n = 2×33 = 66 and 2n+2 = 2(33)+2 = 66+2 = 68

Bingel [31]2 years ago
6 0

Answer:

Are you asking just the next two integers are? If so, they're 135 and 136

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The answer would be a. 288. hope that helped
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Factor 5v^2 - 23v - 10​
AfilCa [17]

Answer:

(5v + 2)(v - 5)

Step-by-step explanation:

Hello!

The expression is written in the form of ax^2 + bx + c

Let's factor by grouping:

ac  = -50

The sum of the factors of -50 should add up to -23.

-25 and 2 work for this.

Expand and factor:

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The factored expression is (5v + 2)(v - 5)

7 0
1 year ago
ANSWER THIS!!! Please?
KIM [24]

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7 0
3 years ago
Which are solutions to the following equation? x^2=21
creativ13 [48]

Answer:

x

=

±

√

21

Explanation:

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4 0
2 years ago
Show all steps to find the product of -3x^3 + 2x - 4 and x^3 + x - 2.
Lana71 [14]

Answer:

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Step-by-step explanation:

Use the distributive property 4 times.

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2 years ago
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