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ICE Princess25 [194]
3 years ago
5

What is the standard form of Y=2/5x+2

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0

The answer to your question is -10

SpyIntel [72]3 years ago
3 0

Answer:

-2x + 5y = 10.

Step-by-step explanation:

Standard form is Ax + By = C  where A, B and C are integers.

y = 2/5x + 2

Multiply through by 5

5y = 2x + 10

-2x + 5y = 10  (answer).

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Running out of time! Please help and show work! Thank you! Will mark brainliest!
VikaD [51]
<h3>​(-3j²k³)²(2j²k)³</h3>

(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.​</em>

​= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>

​= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>

= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.​</em>

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​Answer = 72j¹⁰k⁹

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5 0
3 years ago
Help, I’m stuck. Thank you very much
ZanzabumX [31]
If you notice, the container is really just two circles, with a diameter of 4 each, and a square with sides of 10.5.

now, if we just get the area of each circle, keeping in mind their radius is half of the diameter, namely r = 2, and get the area of the 10.5x10.5 square, sum them up, that'd be the surface area of the container.

\bf \stackrel{\textit{2 circle's area}}{2(\pi r^2)}~~+~~\stackrel{\textit{area of the square}}{10.5\cdot 10.5}&#10;\\\\\\&#10;\stackrel{\textit{2 circle's area}}{2(\pi 2^2)}~~+~~\stackrel{\textit{area of the square}}{10.5\cdot 10.5}\implies 8\pi + 110.25
5 0
3 years ago
In the interval 0° ≤x≤360°, find the values of x for which sin x=-0.8176. Give your answer to the nearest degree.
Alenkasestr [34]

Answer:

235, 305, 55

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Need to know the area of the composite figure.
Deffense [45]

Answer:

  51 m^2

Step-by-step explanation:

The shaded area is the difference between the area of the overall figure and that of the rectangular cutout.

The applicable formulas are ...

  area of a triangle:

     A = (1/2)bh

  area of a rectangle:

     A = bh

  area of a trapezoid:

     A = (1/2)(b1 +b2)h

___

We note that the area of a triangle depends only on the length of its base and its height. The actual shape does not matter. Thus, we can shift the peak of the triangular portion of the shape (that portion above the top horizontal line) so that it lines up with one vertical side or the other of the figure. That makes the overall shape a trapezoid with bases 16 m and 10 m. The area of that trapezoid is then ...

  A = (1/2)(16 m + 10 m)(5 m) = 65 m^2

The area of the white internal rectangle is ...

  A = (2 m)(7 m) = 14 m^2

So, the shaded area is the difference:

  65 m^2 -14 m^2 = 51 m^2 . . . . shaded area of the composite figure

_____

<em>Alternate approach</em>

Of course, you can also figure the area by adding the area of the triangular "roof" to the area of the larger rectangle, then subtracting the area of the smaller rectangle. Using the above formulas, that approach gives ...

  (1/2)(5 m)(16 m - 10 m) + (5 m)(10 m) - (2 m)(7 m) = 15 m^2 + 50 m^2 -14 m^2

  = 51 m^2

7 0
3 years ago
Is 0,4,8,12 an arithmetic sequence?
Aneli [31]
Yes it is!!!! :))) by 4
6 0
2 years ago
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