I think the answer is B.
Hope this helps.
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
Answer:
y = 2x + 3 is the answer
Step-by-step explanation:
Answer:
Linear function 2x+3y=12 .
Step-by-step explanation:
To find y-intercept , make x=0 :
3y = 12
y = 12/3
y = 4 .
To find x-intercept , make y=0 :
2x = 12
x = 12/2
x = 6 .
<u> ! Hope this will help you !</u>
Answer:
Acute Angled Triangle.
Right-Angled Triangle.
Obtuse Angled Triangle
Step-by-step explanation:
a right angle would be 90° angle
obtuse would be over 90°
acute would be smaller than 90°
hope this helps!