3 years ago

I need help with this in math right now I'm struggling

Mathematics

1 answer:

kaheart [24]3 years ago

3 0

Answer:

y=-4x-2

Step-by-step explanation:

linear function, y = mx+c

the y intercept of the graph,c, is -2

thus y = mx - 2

substitute a point on the graph into the equation, (2,-1)

2 = m(-1) -2

m = - 4

thus equation of graph is y = -4x-2

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goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

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Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

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$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

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