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xenn [34]
1 year ago
12

11) A building casts a shadow of 100 feet. The angle of elevation from the end of the shadow to the top of the

Mathematics
1 answer:
svp [43]1 year ago
5 0

Answer:

≈ 27 ft

Step-by-step explanation:

using the tangent ratio in the right triangle formed by the building and the ground.

tan15° = \frac{opposite}{adjacent} = \frac{?}{100} ( multiply both sides by 100 )

100 × tan15° = ? , then

? ≈ 27 ft ( to the nearest whole number )

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Given the function h(a) = -x^2+ 7x + 14, determine the average rate of change
Yakvenalex [24]

Answer:

- 2

Step-by-step explanation:

The average rate of change of h(x) in the closed interval [a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [a, b ] = [1, 8 ], thus

f(b) = f(8) = - 8² + 7(8) + 14 = - 64 + 56 + 14 = 6

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6 0
2 years ago
I don't get it and I have tried it multiple ways
jasenka [17]

9514 1404 393

Answer:

  9350 m²

Step-by-step explanation:

There are several ways you can go at this. Here are 3 of them:

  1. along an extension of the lower right vertical edge, divide the figure into a rectangle and a right triangle.
  2. between the upper left corner and the inside corner at lower right draw a diagonal line to divide the figure into a trapezoid and a triangle.
  3. subtract the area of the trapezoid at the right from the area of the bounding rectangle

__

The relevant formulas for area are ...

  rectangle: A = LW . . . . . . . . . . . length times width

  trapezoid: A = (1/2)(b1 +b2)h . . . b1, b2 are the bases, h is the height

  triangle: A = (1/2)bh . . . . . . . . . . . b is the base, h is the height

__

Here's what those computations look like:

1. rectangle: 60m wide by 80 m high = 4800 m².

  right triangle: base 190-60 = 130 m; height = 80-10 = 70 m.

     area = (1/2)(130 m)(70 m) = 4550 m²

  figure area = 4800 m² +4550 m² = 9350 m² . . . . area of figure

__

2. The trapezoid has bases of 80 m and 10 m, and a height of 60 m. Its area is ...

  A = (1/2)(80 m +10 m)(60 m) = 2700 m²

The triangle has a base of 190 m and a height of 80-10 = 70 m. Its area is ...

  A = (1/2)(190 m)(70 m) = 6650 m²

Then the total area is 2700 m² +6650 m² = 9350 m² . . . total area

__

3. The bounding rectangle is 190 m by 80 m, so its area is ...

  A = LW = (190 m)(80 m) = 15200 m²

The (negative) trapezoid at right has bases of 10 m and 80 m, and a width of 190-60 = 130 m. Its area is ...

  A = (1/2)(10 m +80 m)(130 m) = 5850 m²

The area of the figure is the difference between these:

  figure area = 15200 m² -5850 m² = 9350 m² . . . figure area

7 0
3 years ago
Please help thanks!!
bogdanovich [222]
The answer is 1.) because when dividing you subtract the exponents.
3 0
2 years ago
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