Initial mass: 34g
Daily reduction: 2.49g
The tumor mass, as function of days, is:
m(t)=34-2.49t, where t is time in days.
In the first day, t=0, mass is m(0)=34g. Next day, t=1, mass is m(1)=34-2.49.
After 5 days: m(5)=34-2.49×5=21.55g.
Answers: m(t)=34-2.49t
After 5 days: m(5)=21.55g
Both are correct because 3/12 can be simplified to 1/4 :
3÷3=1
12÷3=4
3/12= 1/4
hope this helped
Answer:
Ruben needs a new job
Step-by-step explanation: