Answer:
what are the listed followings ?
Step-by-step explanation:
Step-by-step explanation:
There is figures in you question. Please check your question.
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
Is there a table? Can you attach a picture of it?
Answer:
x = 1
Step-by-step explanation:
Given:
We are asked to solve for x when the function is equal to zero.
<u>We should have</u>: 0 = -4x + 4
<u>Solve</u>
1. Subtract 4 from both sides
0 - 4 = -4x + 4 - 4
-4 = -4x
2. Divide both sides by -4
-4 ÷ -4 = -4x ÷ 4
1 = x
