1. Structure of an atom:-
The basic structure of an atom includes a tiny, relatively massive nucleus, containing at least one proton and usually one or more neutrons.Outside of the nucleus are energy levels (also called shells), which contain one or more electrons.
Properties of an atom:-
The neutrons have the greatest mass and have no charge. The protons have slightly less mass than the neutrons and are positively charged. The electrons have almost no mass and are negatively charged. The chemical properties of the atom are determined by the number of protons, in fact, by number and arrangement of electrons.
2. Elements and their chemical symbols :-
1) Sodium - Na
2) Carbon - C
3) Magnesium - Mg
4) Aluminium - Al
5) Silicon - Si
6) Chlorine - Cl
7) Potassium - K
8) Calcium - Ca
9) Copper - Cu
10) Iron - Fe
3. ionic bond
Covalent bond
Metallic bond
4. pH scale used to specify the acidity or basicity of an aqueous solution. Acidic solutions are measured to have lower pH values than basic or alkaline solutions
5. There are four natural states of matter: Solids, liquids, gases and plasma.
6. Law of conservation of mass :
The 'law of conservation of mass' says that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. The mass of the products in a chemical reaction must equal the mass of the reactants.
Law of conservation of energy :-
According to the law of conservation of energy, energy can only be transformed from one form to another. It can neither be created nor destroyed. The total energy before and after the transformation always remains constant.
Answer:
The conservation of momentum states that, within some problem domain, the amount of momentum remains constant; momentum is neither created nor destroyed, but only changed through the action of forces as described by Newton's laws of motion. ... Momentum is conserved in all three physical directions at the same time.
Because they can live on water and land
Answer:
56.4 mmHg
Explanation:
Given:
Vapor pressure of the solution, P solution = 55 mmHg
The mass of sucrose (C₆H₁₂O₆) = 10 g
Also, Molar mass of sucrose (C₆H₁₂O₆) = 180 g/mol
So, moles = Given mass/ molar mass
Hence, moles of sucrose in the solution = 10 g / 180 g/mol = 0.05556 mol
Given that: Mass of ethanol = 100 g
Molar mass of ethanol = 46 g/mol
Hence, moles of ethanol = 100 g / 46 g/mol = 2.174 mol
Mole fraction of solvent, ethanol is:
X ethanol = 2.174 mol / (2.174 + 0.05556) mol = 0.975
Applying Raoult's Law
P solution = X ethanol*P° ethanol
<u>
=> P° ethanol = P solution / X ethanol = 55 mmHg / 0.975 = 56.4 mm Hg</u>
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