3 years ago

Please explain how we judge the brightness of stars.

1 answer:

6 0

Astronomers can measure it by way of luminosity which is the power of a star or the amount of energy (light) the star admits from its surface. they also measure the brightness of a start as if it were to appear 32.6 light years from Earth

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En el aire que respiramos y en el aire comprimido de los tanques de los buzos se encuentra, además de oxígeno, el gas nitrógeno

marysya [2.9K]

Answer: can someone please translate so i can answer.

Explanation:

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3 years ago

A sealed container at 25oC contains a gas at a pressure of 104 kPa. What is the pressure of the gas when it is heated to 225oC?

seropon [69]

Answer:

174 kPa

Explanation:

Given that,

Initial temperature, T₁ = 25° C = 25+273 = 298 K

Final temperature, T₂ = 225°C = 225 + 273 = 498 K

Initial pressure, P₁ = 104 kPa

We need to find the new pressure. The relation between the temperature and pressure is given by :

$\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

So,

$P_2=\dfrac{P_1T_2}{T_1}\\\\P_2=\dfrac{104\times 498}{298}\\\\P_2=173.79\ kPa$

P₂ = 174 kPa

So, the new pressure is 174 kPa.

4 0

3 years ago

Check my answers please! 1.Which of the following conditions increases the number of collisions between reactant molecules in a

NikAS [45]

<span>I was correct... 1 is adding more reactant molecules and 2 was decreasing in ch3br concentration over time </span>

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3 years ago

6. What will happen to the gravitational force between stars as the universe continues to expand?

Julli [10]

<h2><em>Nothing will happen to them</em></h2>

please mark brainliest

8 0

2 years ago

Please help thank you! And how many significant figures does it have?

zheka24 [161]

Answer:

0.779 cube centimetres

Explanation:

density = mass divided by volume

$d=\frac{m}{v}$ rearrange the equation to solve for volume: $v=\frac{m}{d}$

plug in the corresponding values:

volume = 6.130 g / 7.87 (gcm^3)

the gs cancel, the answer will be 0.7789

we will round to three sig figs, since that's the lowest amount of figures in the given values: ~0.779 cm^3

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2 years ago