Can you help me with this?

Aakesh has two bags of marbles. The first bag contains 6 red marbles, 4 blue

Orlov [11]

The answer for the 1st bag is option B = 1/3

The answer for the 2nd bag is option C = 5/9

Number of marbles in 1st bag - 15 (6 red, 4 blue & 5 green)

Number of marbles in 2nd bag - 9 (3 red, 1 blue & 5 green)

The formula of probability = Total number of events in the outcome /total number of outcomes.

Now the probability that Aakesh will select a green marble from the 1st bag is 5(green marbles)/15(total number of marbles in 1st bag)

That is 5/15=1/3

Now the probability that Aakesh will select a green marble from the 2nd bag is 5(green marbles)/9(total number of marbles in 1st bag)

That is 5/9

To know more about probability go to - https://brainly.in/question/17157610?msp_poc_exp=6

7 0

1 year ago

Read 2 more answers

The tables below show running hours of three printers that produce greeting cards and the total number of greeting cards produce

AysviL [449]

ANSWER

The correct answer is A

EXPLANATION

To find the ink cost of each card coming from printer B, we need to find the total cost from printer B and the total number of cards printed by Printer B.

The total hours of all the three printers over the three weeks

$=40+45+55+50+50+30+45+40+60=415$

The total hours of printer B only

$=50+50+30=130$

Total number of cards produced over the three weeks

$=7950+7800+9600=25350$

We can use ratio and proportion to determine the total cards produce by printer B only.

$415:25350$

$130:x$

If less, more divides

$x=\frac{130\times 25350}{415} \approx7941$

Total cost of Printer B in 130 hours

$ $=130 \times 15=1950$

The ink cost

$=\frac{1950}{7941}$

$=0.2456$

$ $\approx 0.30$

to 2 decimal places

8 0

3 years ago

Read 2 more answers

Math again yay!...Ew math

Sliva [168]

Answer:

The graph of g(x) is wider.

Step-by-step explanation:

Parent function:

$f(x)=x^2$

New function:

$g(x)=\left(\dfrac{1}{2}x\right)^2=\dfrac{1}{4}x^2$

Transformations:

For a > 0

$f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}$

$f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}$

$\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of}\:a\\ & \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\ & \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a\\\end{aligned}$

$\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of} \: a\\& \textsf{If }a > 1 \textsf{ it is compressed by a factor of}\: a\\ & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of}\: a\\\end{aligned}$