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Anna [14]
3 years ago
14

PLEASE HELP, I NEED THIS QUICK!

Mathematics
1 answer:
denis23 [38]3 years ago
8 0

Answer:

Step-by-step explanation:

becasue  you can square a negative number

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HELP ASAP!!!!!!!!<br><br> Find the cite of each variabile
katrin [286]

tan = opp/adj

x = 13(tan 45)

x = 13

//

a² + b² = c²

13² + 13² = 338²

square root of 338 is not a rational number so turn into mixed radical.

//

x \: = 13

y = 13 \sqrt{2}

5 0
2 years ago
An asteroid is 10^{8} miles away from earth, and it is traveling at a speed of 10^{5} miles per day.
Inessa05 [86]

Divide the distance by the speed:

10^8 / 10^5 = 10^3 days ( 1,000 days)

6 0
3 years ago
A florist sells 3 dozen bunches of flowers for $78. whites the cost per flower?
steposvetlana [31]
3x12= 36 flowers for $78

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4 0
3 years ago
Explain how to use mental math to express 12/25 as a percent
o-na [289]

Answer:

Step-by-step explanation:

12/25 =

12 ÷ 25 =

0.48 =

0.48 × 100/100 =

0.48 × 100% =

(0.48 × 100)% =

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8 0
3 years ago
A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i
garri49 [273]

Answer:

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :  

Null hypothesis:\mu \leq 5  

Alternative hypothesis:\mu > 5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

6 0
3 years ago
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