Question

Select the two values of x that are roots of this equation. x2 + 3x - 3 = 0

Answer 1

Answer:

        A. $\bold {x=\dfrac{-3+\sqrt{21}}{2}}$ and  D.   $\bold {x=\dfrac{-3-\sqrt{21}}{2}}$

Step-by-step explanation:

$x^2 + 3x - 3 = 0\\a=1\,,\ \ b=3\,,\ \ c=-3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-3\pm\sqrt{3^2-4\cdot1\cdot(-3)}}{2\cdot1}=\dfrac{-3\pm\sqrt{9+12}}{2}=\dfrac{-3\pm\sqrt{21}}{2}$