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vazorg [7]
3 years ago
14

HELP HELP

Mathematics
1 answer:
serious [3.7K]3 years ago
5 0
10.5 is the answer to your question
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The velocity of a particle moving back and forth on a line is vequalsStartFraction ds Over dt EndFraction equals6 sine (2 t )Sta
max2010maxim [7]

Answer:

s = 6 m

Step-by-step explanation:

The value of the velocity v is given as:

v = \frac{ds}{dt} = 6 sin(2t) m/s

To find s, we have to integrate and apply the initial values of s = o when t = 0:

\frac{ds}{dt} = 6 sin(2t)\\\\\int\limits^s_0 {ds} = \int\limits^t_0 {6sin(2t)} \, dt\\\\s|^s_o = -3cos(2t)|^t_o\\\\s - 0 = -3cos(2t) -(-3cos(0))\\\\s = -3cos(2t) + 3(1)\\\\s = -3cos(2t) + 3

When t = π/2, s will be:

s = -3cos(2 * π/2) + 3

s = -3cos(π) + 3

s = -3(-1) + 3

s = 3 + 3

s = 6 m

4 0
4 years ago
I need help with this
balandron [24]
Here you go! Hope this helps

6 0
3 years ago
How do I graph this problem X+2y= -2
aleksandr82 [10.1K]
If you have an app like Desmos, you can just input that. If not, you would subtract X from both sides to get 2y=-x-2. Then, you would divide by 2 on both sides to get y=-1/2x-1. You can input that into Desmos or a graphing calculator. Please mark me brainliest, but its fine if you don’t want to. Have a good day!
7 0
3 years ago
Necesito la respuesta a este problema, me ayudarían mucho, gracias
DanielleElmas [232]
Yo diría x igual a 10.66
6 0
3 years ago
The depth of a lake is 15.8 m.
lorasvet [3.4K]

Answer:

A) 16

B) 0.2

C) 1.27

6 0
3 years ago
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