What cell function produces offspring

Individual solute particles are broken apart from the solid by these particles. * a Solution b Insoluble c Solvent d Compounds

Maru [420]

Answer:

Individual solute particles are broken apart from the solid by the;

c. Solvent

Explanation:

A solution is the homogeneous mixture that is made up of two or more substances formed by dissolving a substance which can be a solid, liquid or gas in another substance known as the solvent which normally the larger part of the fraction of the solution than the solute and can also be a solid, liquid or a gas

In a solution the solvent particles serves to brake of and disperser parts of a solid solute to form a more or less homogeneous mixture

Therefore, the solute particles are broken by the <u>solvent</u> particles in a solution

7 0

3 years ago

water at 400 kPa and 60°C while the other part is evacuated. The partition is now removed, and the water expands to fill the ent

kaheart [24]

Answer:

0.4912 kJ/K

Explanation:

Using steam table, the properties of water at stage 1 can be determined:

$P_{1}$ = 400 kPa

$T_{1}$ = 60°C

Therefore, from steam table:

specific volume $v_{1} = 0.001017 m^{3}/kg$

entropy $s_{1} = 0.8313 kJ/kg*K$

Calculating the specific volume of water after the partition is removed, since the mass is constant and volume of water is doubled:

$v_{2} = 2*0.001017 = 0.002034 m^{3}/kg$

Final pressure of water in the tank = $P_2} = 40 kPa$

dryness factor after removing the partition

$x = \frac{0.002034 - 0.001026}{3.993 - 0.001026} = 2.524*10^{-4} kg/vapor$

Therefore:

$s_{2} = s_{f2} + x*s_{fg2} = 1.0261 + (2.524*10^{-4}*6.643) = 1.02778 kJ/kg*K$

Thus, the entropy change is:

Δs = $m*(s_{2}-s_{1}) = 2.5*(1.02778 - 0.8313) = 0.4912 kJ/K$

Therefore, the entropy change of water is 0.4912 kJ/K

6 0

4 years ago

Xylem contains specialized cells that provide support for a plant stem. how does the structure of one of these cells help it car

zepelin [54]

Answer:

Xylem is the specialised tissue of vascular plants that transports water and nutrients from the plant–soil interface to stems and leaves, and provides mechanical support and storage. ... The water‐conducting xylem cells provide an internal hydrophobic surface facilitating water transport as well as mechanical strength.

3 0

3 years ago

Read 2 more answers

What is h2o? I’m in 1st grade

Crazy boy [7]

Answer:

Water

Explanation:

H20 means

H = Hydrogen

2 = 2 Hydrogen atoms

O = Oxygen (1 atom)

Thanks!

Mark me brainliest!

5 0

3 years ago

Read 2 more answers

A. 14.8

Scilla [17]

Answer:

Explanation:

1)

Given data:

Initial volume = 2.5 L

Initial temperature = 300 k

Final temperature = 80 k

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 2.5 L × 80 K / 300 k

V₂ = 200 L.K / 300 K

V₂ = 0.67 L

2)

Given data:

Initial volume = 752 mL

Initial temperature = 25.0°C (25+273 = 298 K)

Final temperature = 50.0°C(50+273 = 323 K)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 752 mL × 323 K / 298 k

V₂ = 242896 mL.K / 298 K

V₂ = 815.1 mL

3)

Given data:

Initial volume = 2.75 L

Initial temperature = 20°C (20+273 = 293 K)

Final temperature = ?

Final volume = 2.46 L

Solution:

The given problem will be solve through the Charles Law.

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁/V₁

T₂ = 2.46 L × 293 K / 2.75 L

T₂ = 720.78 L.K / 2.75 L

T₂ = 262.1 K

4)

Given data:

Initial volume = 1500 L

Initial temperature = 5°C (5+273 = 278 K)

Final temperature = 30 °C(30+273 = 303 K)

Final volume of heated air = ?

Solution:

The given problem will be solve through the Charles Law.

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 1500 L × 303 K / 278 k

V₂ = 454500 L.K / 278 K

V₂ = 1634.89 L

5)

Given data:

Initial volume = 15.5 L

Initial temperature = 20°C (20+273 = 293 K)

Final temperature = 7.0 °C(7.0+273 = 280 K)

Final volume of balloon = ?

Solution:

The given problem will be solve through the Charles Law.

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 15.5 L × 280 K / 293 k

V₂ = 4340 L.K / 293 K

V₂ = 14.8 L

6)

Given data:

Initial volume = 150 mL

Initial temperature = 23.5°C (23.5+273 = 296.5 K)

Final temperature = 72.5 °C(72.5+273 = 345.5 K)

Final volume of balloon = ?

Solution:

The given problem will be solve through the Charles Law.

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 150 mL × 345.5 K / 296.5 k

V₂ = 51825 mL.K / 296.5 K

V₂ = 174.79 mL

6 0

3 years ago