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Mamont248 [21]
3 years ago
15

1) The crystal of potassium chloride is composed of A) potassium chloride molecules B) potassium atoms and chlorine atoms C) pot

assium atoms and chloride ions D) potassium ions and chloride ions
Chemistry
1 answer:
TiliK225 [7]3 years ago
8 0

Answer:

answer is D) potassium ions and chloride ions

Explanation:

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Determine the number of atoms of O in 60.1 moles of Fe₂(SO₃)₃.
kvasek [131]

Answer:

3.310308*10^26

Explanation:

nO=9nFe2(SO3)3=9*60.1=540.9 moles

number of atoms: 540.9*6.02*10^23

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The partial pressure of hellium gas in a gaseous mixture of hellium and hydrogen is<br>​
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The partial pressure of helium gas in a gaseous mixture of helium and hydrogen is the pressure that the helium would exert in the absence of the hydrogen. equal to the total pressure divided by helium's molar mass. O equal to the total pressure divided by the number of helium atoms present.

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3 years ago
What us the balanced equation between an alkali and acid ​
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alkalyene ch2+2n+h wbqlzl

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True or false? Salt water takes a shorter time to boil than regular water.<br><br> Send help!!!!
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false

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Explanation:

3 0
3 years ago
What is the percent yield for the reaction below when
kumpel [21]

Answer:

Percent yield of reaction is<em> 150%.</em>

Explanation:

Given data:

Percent yield = ?

Actual yield of SO₃ = 586.0 g

Mass of SO₂ = 705.0 g

Mass of O₂ = 80.0 g

Solution:

Chemical equation:

2SO₂ + O₂      →     2SO₃

Number of moles of SO₂:

Number of moles = mass/ molar mass

Number of moles = 586.0 g/ 64.1 g/mol

Number of moles = 9.1 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 80.0 g/ 32g/mol

Number of moles = 2.5 mol

Now we will compare the mole of SO₃ with O₂ and SO₂.

                      SO₂          :          SO₃

                        2             :            2

                     9.1              :           9.1

                       O₂            :          SO₃

                        1              :            2

                     2.5             :           2×2.5 = 5

The number of moles of SO₃ produced by oxygen are less it will limiting reactant.

Theoretical yield of SO₃:

Mass = number of moles × molar mass

Mass = 5 mol × 80.1 g/mol

Mass = 400.5 g

Percent yield of reaction:

Percent yield = actual yield / theoretical yield  × 100

Percent yield = 586.0 g/ 400.5 g× 100

Percent yield = 1.5× 100

Percent yield = 150%

8 0
3 years ago
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