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const2013 [10]
3 years ago
13

Sophie bikes at a speed of s miles per hour. Her friend Rana is slower, her biking speed is only r miles per hour. The route Sop

hie traveled took her t hour. How long was the route.
Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
3 0
Well i think you might be missing something, there is no numbers
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Pls help me with this
Anit [1.1K]

Answer:

hope this will help you more

8 0
3 years ago
SIMPLIFY THE EXPRESSION.<br> 9(1 - 7x)
jok3333 [9.3K]

Answer:

9-63x

Step-by-step explanation:

9(1-7x)

9-63x

7 0
4 years ago
Read 2 more answers
Please answer the picture
dimaraw [331]
The area is equal to 230 CM.
area for rectangle :
area = width times length
area = 7 x 20 = 140CM
area for triangle:
area = 1/2 times base times height
area = 1/2 x 20 x 9 = 90CM

ADD:
140+90 = 230 CM
3 0
3 years ago
Read 2 more answers
Write a quadratic function f whose zeros are 3 and -10.<br> f(x) =
andreyandreev [35.5K]

Answer:

f(x)= x^2 + 7x - 30

5 0
3 years ago
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
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