All categories

3 years ago

What is the next number in the following Lucas sequence? 1, 3, 4, 7, 11... a. 18 c. 15 b. 13 d. 17

Mathematics

2 answers:

Basile [38]3 years ago

7 0

D.17 would be the correct answer.

Tcecarenko [31]3 years ago

6 0

Answer:

Actually the answer is A. 18

Step-by-step explanation:

You might be interested in

What is 3 x 10,000 + 4 x 1,000 + 6 x 100 + 8 x 10 + 8 written in standard form?

Talja [164]

Answer:

thirty four thousand six hundred and eighty eight

Step-by-step explanation:

4 0

3 years ago

. Find the area of a square with a side of 2v3.

Vlad1618 [11]

Answer:

$area = 2 \sqrt{3} \times 2 \sqrt{3} \\ = 4( { \sqrt{3} })^{2} \\ = 4 \times 3 \\ = 12 \: {units}^{2}$

6 0

3 years ago

100.5 divided by 1.5

wariber [46]

The answer to 100.5 divided by 1.5 is 67

5 0

3 years ago

Casey deposited $1,450 in a bank account with an interest rate of 4%. How much simple interest was earned in two years?

vekshin1

Answer:

$116

Step-by-step explanation:

The Simple Interest formula is i = prt. Here,

i = ($1,450)(0.04)(2 yr) = $116

3 0

3 years ago

What is the simplified form of the following expression? 7(^3 square root 2x) - 3 (^3 square root 16x) -3 (^3 square root 8x)

Pachacha [2.7K]

Answer:

The third option listed: $\sqrt[3]{2x} -6\sqrt[3]{x}\\$

Step-by-step explanation:

We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):

$7\sqrt[3]{2x} -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x} -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x} -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}$

And now we combine all like terms (notice that the only two terms we can combine are the first two, which contain the exact same radical form:

$7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}=\\=\sqrt[3]{2x} -6\sqrt[3]{x}$

Therefore this is the simplified radical expression: $\sqrt[3]{2x} -6\sqrt[3]{x}\\$

5 0

3 years ago