the table:4 represents a linear function.
What is system of linear equations?
The intersections or meetings of the lines or planes that represent the linear equations are known as the solutions of linear equations. The set of values for the variables in every feasible solution is a solution set for a system of linear equations.
Not a Solution
If there is no intersection of any lines, or if the graphs of the linear equations are parallel, then the system of linear equations cannot be solved.
An Endless Number of Options
A set of infinite points exists for which the L.H.S. and R.H.S. of an equation become equal, indicating that a system of linear equations has an infinite number of solutions.
Unique fixing a series of linear equations
For table 4: The slope will be (8-6)/(3-5) = 2/-2 = -1
and (10-8)/(1-3) = 2/-2 = -1
Hence, the table:4 represents a linear function.
For a function to be linear the slope of all the segments should be same.
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Answer:
figure please...... I cant see the figure
Answer:
6
Step-by-step explanation:
Pull terms out from of the radical,assuming positive real numbers .
These are a lot easier when they r like this...no coefficient in front of ur x^2.
x^2 + 5x - 14....u see ur last sign, the -.....this tells me that in ur 2 factors, both signs will be different....one is positive and one is negative. U see ur first sign, the +, this tells me that ur bigger number will be positive.
Now we just have to find 2 numbers, that when added = 5 and when multiplied = 14, So ur 2 numbers are 7 and 2.
(x^2 + 5x - 14) =
(x + 7)(x - 2) <===
To answer this question, first calculate the z-score:
test score - mean score 65 - 70
z = ----------------------------------- = ------------------- = -5/10 = -0.5
std. dev. 10
We need to determine the area under the normal curve to the left of z = -0.5.
Refer to a table of z-scores, and look for z=-0.5. What area appears in connection with this z-score? It's less than 0.5000.
Using my TI-83 Plus calculator (specifically, its "normalcdf( " function, I found that the area under the std. normal curve to the left of z = -0.5 is 0.309.
Thus, the percentile is 30.9, or roughly 31 (31st percentile).
Roughly 31% of students earned a grade lower than 65, and roughly 69% earned a higher grade.