The diameter of a circle is 8 meters. What is the circle's circumference?
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CO = AO = 32 (Are rays.)
BO = BC + CO = 98 + 32 = 130
AB ⊥ BO
⇒ ΔAOB is a rectangular triangle.
We use Pitagora's theorem.
CO = AO = 32 (Are rays.)
BO = BC + CO = 98 + 32 = 130
AB ⊥ BO
⇒ ΔAOB is a rectangular triangle.
We use Pitagora's theorem.
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