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3 years ago

6

Mark spends $36 at a basketball game. He buys a T-shirt for $22. He then buys a bottle of water for $4 and 2 tacos. How much is

each taco?

2 answers:

Lady bird [3.3K]3 years ago

7 0

Answer:

each taco is $5.

Step-by-step explanation:

Let's think about like Mark starts off with $36. Take away $22 for that t-shirt he bought. Now he has $14. He uses $4 for water, now he has $10. The rest of his money is spent on tacos. $10/2 tacos is $5 for each taco. :)

Arturiano [62]3 years ago

5 0

Answer:

each taco is $7.

Step-by-step explanation:

In total he spent $36. He bought a shirt for $22 and a bottle of water for $4.

22+4= 26

36-22= 14

14 divided by 2= 7

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Answer:

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Step-by-step explanation:

It's decreasing by 7

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jek_recluse [69]

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3 years ago

Is 2,12 4,24 6,36 8,48 10,60 proportional

Elena L [17]

Answer:

Yes

Step-by-step explanation:

12 divided by 2 = 6, 24 divided by 4 = 6, 36 divded by 6 = 6, 48 divded by 8 = 6, 60 divided by 10 = 6.

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3 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

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2 years ago

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Answer:

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Step-by-step explanation:

The side ratios are ...

24 : 45 : 51 = 8 : 15 : 17

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__

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