Given Information:
Current = I = 28 A
distance between wires = r = 2.0 m
Required Information:
Magnetic field = B = ?
Answer:
B = 12x10⁻⁶ T
Step-by-step explanation:
Biot-Savart Law is given by
B = μ₀I/2πr
Where μ₀ is the permeability of free space, I is the current flowing through the wire and B is the magnitude of the magnetic field produced.
We are asked to find the magnetic field midway between the wires so r/2 = 1
B = 4πx10⁻⁷*28/2π*1
B = 6x10⁻⁶ T
since the same amount of current flows in both wires therefore, equal amount of magnetic field will be produced in both wires
B = 2*6x10⁻⁶ T
B = 12x10⁻⁶ T
Therefore, the net magnetic field midway between the two wires is 12x10⁻⁶ T.
Answer:
1234285.7 m or 1234.3 km
Explanation:
Let the distance be
, the time taken by P waves be
and the time taken by the S waves be
.


For the P waves,


For the S waves,


Equating the
,

Divide both sides of the equation by 500 to reduce the terms.

Since S waves arrive 2 minutes (= 120 seconds) after P waves,


Substitute this in the equation of the distance.




Substitute this in the equation for
involving
.



By copying their genomes, they retain the tool kit and at the same time generate a garage full of spare parts. Gene duplication can provide the raw material for expression changes to occur, and polyploidy itself can trigger epigenetic changes
Capacitance is a measure of charge stored per volt.
Answer:
(C) The frequency decrease and intensity decrease
Explanation:
The Doppler effect describes the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source, or the wave source is moving relative to the observer, or both.
if the observer and the source move away from each other as is the case for this problem, the wavelength heard by the observer is bigger.
The frequency is the inverse from the wavelength, so the frequency heard will increase.
The sound intensity depends inversely on the area in which the sound propagates. When the buzzer is close, the area is from a small sphere, but as the buzzer moves further away, the wave area will be from a larger sphere and therefore the intensity will decrease.