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densk [106]
3 years ago
13

8. A baseball is hit upward and travels along a parabolic arc before it strikes the se

Physics
1 answer:
Usimov [2.4K]3 years ago
8 0

d. The x-component of the velocity of  the ball is the same througout the  ball's flight

Explanation:

The motion of the baseball is a projectile motion, which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction.

From this description, we can already see that the correct statement is D: in fact, there is no force acting in the horizontal direction on the ball (if we neglect air resistance), therefore the acceleration in the x-direction is zero, therefore the x-component of the velocity is constant.

The other statements are wrong because:

a.  The acceleration of the ball  decreases as the ball moves upward. --> false because the acceleration remains the same (g=9.8 m/s^2 downward)

b.  The velocity of the ball is zero m/s  when the ball is at the highest point  in the arc.​ --> false because only the y-component of the ball's velocity is zero at the highest point, but the x-component is not zero

c. The acceleration of the ball is zero  m/s when the ball is at the highest  point in the arc. --> false because the  acceleration remains the same (g=9.8 m/s^2 downward)

Therefore the correct answer is

d. The x-component of the velocity of  the ball is the same througout the  ball's flight

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

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A Carnot engine absorbs 1, 3 MJ of heat at 427 degree C and exhausts heat to a reservoir at 90 degree C. How much work does it d
Alex17521 [72]
<span>Carnot cycle efficiency = work done/heat supplied = (Th - Tc)/Th where, Th is temperature of hot reservoir and Tc is temperature of cold reservoir. we have given the values as Heat supplied = 1.3 MJ or 1300 KJ, Th = 427 degree C and Tc = 90 degree C. converting degree Celsius to kelvin temperatures, Th = 427 + 273 = 700 K Tc = 90 +273 = 363 solving equations, (700 - 363)/700 = work done / 1300 work done = 625.86 KJ i.e. 0.626 MJ work is done .</span>
5 0
3 years ago
Why does moon appear to have alot of phases
Bingel [31]
It depends on the angle of the earth, and our point of view. A full moon would occur if we were to be right in front of it.
4 0
3 years ago
How do rocks within Earth change as P waves pass? How do rocks within Earth change as P waves pass? Rocks within Earth both expa
ohaa [14]

Rocks within Earth both expand and contract as P waves pass

Explanation:

Rocks within the earth both expands and contracts as P-waves passes through them. P-waves are elastic waves.

  • Elastic waves behaves in such a way that they do not cause permanent deformation of rocks.
  • They can be said to cause elastic deformation when they travel through rocks.
  • They simply temporarily expand and contract the rock within a short period by causing the vibration of particles of the medium.
  • After a short while, the rock returns back to its original position as if nothing has happened to it.
  • These elastic waves are better called seismic waves.
  • P-waves are primary waves that can travel through any medium.

Learn more:

Earthquakes brainly.com/question/11292835

#learnwithBrainly

6 0
3 years ago
Mrs. LaCross leaves school and accidentally leaves her coffee mug on the roof of her car as shown in the picture below.
aleksandrvk [35]

Answer:

When she stops at a fast pace the energy and wind will take the cup forward and it will most likeley brake

Explanation:

I'm not entirely sure this is what you were looking for but I hope this helped!

PLEASE MARK ME AS BRAINLIEST

8 0
3 years ago
A girl of mass 55 kg throws a ball of mass 0.80 kg against a wall. The ball strikes the wall horizontally with a speed of 25 m/s
lisabon 2012 [21]

Answer:

Magnitude of the average force exerted on the wall by the ball is 800N

Explanation:

Given

Contact Time = t = 0.05 seconds

Mass (of ball) = 0.80kg

Initial Velocity = u = 25m/s

Final Velocity = 25m/s

Magnitude of the average force exerted on the wall by the ball is given by;

F = ma

Where m = 0.8kg

a = Average Acceleration

a = (u + v)/t

a = (25 + 25)/0.05

a = 50/0.05

a = 1000m/s²

Average Force = Mass * Average Acceleration

Average Force = 0.8kg * 1000m/s²

Average Force = 800kgm/s²

Average Force = 800N

Hence, the magnitude of the average force exerted on the wall by the ball is 800N

3 0
4 years ago
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