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3 years ago

8. A baseball is hit upward and travels along a parabolic arc before it strikes the se

Physics

1 answer:

Usimov [2.4K]3 years ago

8 0

d. The x-component of the velocity of the ball is the same througout the ball's flight

Explanation:

The motion of the baseball is a projectile motion, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction.

From this description, we can already see that the correct statement is D: in fact, there is no force acting in the horizontal direction on the ball (if we neglect air resistance), therefore the acceleration in the x-direction is zero, therefore the x-component of the velocity is constant.

The other statements are wrong because:

a. The acceleration of the ball decreases as the ball moves upward. --> false because the acceleration remains the same ( $g=9.8 m/s^2$ downward)

b. The velocity of the ball is zero m/s when the ball is at the highest point in the arc. --> false because only the y-component of the ball's velocity is zero at the highest point, but the x-component is not zero

c. The acceleration of the ball is zero m/s when the ball is at the highest point in the arc. --> false because the acceleration remains the same ( $g=9.8 m/s^2$ downward)

Therefore the correct answer is

d. The x-component of the velocity of the ball is the same througout the ball's flight

Learn more about projectile motion:

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Answer : The mass of $NaN_3$ required is 71.175 grams.

Explanation :

To calculate the moles of nitrogen gas, we use the equation given by ideal gas :

PV = nRT

where,

P = Pressure of nitrogen gas = 763 torr

V = Volume of the nitrogen gas = 40.0 L

n = number of moles of gas = ?

R = Gas constant = $62.364\text{ L.torr }mol^{-1}K^{-1}$

T = Temperature of helium gas = $25^oC=273+25=298K$

Putting values in above equation, we get:

$763torr\times 40.0L=n\times 62.364\text{ L.torr }mol^{-1}K^{-1}\times 298K\\\\n=1.642mol$

Now we have to calculate the moles of $NaN_3$ .

The balanced chemical reaction is:

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the balanced chemical reaction, we conclude that

As, 3 moles of $N_2$ produced from 2 moles $NaN_3$

So, 1.642 moles of $N_2$ produced from $\frac{2}{3}\times 1.642=1.095$ moles $NaN_3$

Now we have to calculate the mass of $NaN_3$ .

Molar mass of $NaN_3$ = 65 g/mol

$\text{Mass of }NaN_3=\text{Moles of }NaN_3\times \text{Molar mass of }NaN_3$

$\text{Mass of }NaN_3=1.095mole\times 65g/mole=71.175g$

Therefore, the mass of $NaN_3$ required is 71.175 grams.

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Answer:

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Im fairly certain that the answer would be D, and this is because of the law of conservation of energy/momentum.