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densk [106]
3 years ago
13

8. A baseball is hit upward and travels along a parabolic arc before it strikes the se

Physics
1 answer:
Usimov [2.4K]3 years ago
8 0

d. The x-component of the velocity of  the ball is the same througout the  ball's flight

Explanation:

The motion of the baseball is a projectile motion, which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction.

From this description, we can already see that the correct statement is D: in fact, there is no force acting in the horizontal direction on the ball (if we neglect air resistance), therefore the acceleration in the x-direction is zero, therefore the x-component of the velocity is constant.

The other statements are wrong because:

a.  The acceleration of the ball  decreases as the ball moves upward. --> false because the acceleration remains the same (g=9.8 m/s^2 downward)

b.  The velocity of the ball is zero m/s  when the ball is at the highest point  in the arc.​ --> false because only the y-component of the ball's velocity is zero at the highest point, but the x-component is not zero

c. The acceleration of the ball is zero  m/s when the ball is at the highest  point in the arc. --> false because the  acceleration remains the same (g=9.8 m/s^2 downward)

Therefore the correct answer is

d. The x-component of the velocity of  the ball is the same througout the  ball's flight

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

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t = 0.192 \mu m

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here we know that

\mu = 1.79

now total shift in the bright fringe is given as

Shift = \frac{D(\mu - 1)t}{d}

Also we know that the fringe width of maximum intensity is given as

\delta x = \frac{\lambda D}{d}

now we have

\frac{D}{d} = \frac{\delta x}{\lambda}

now the shift is given as

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given that the shift is

Shift = 0.37 \delta x

here we have

0.37 \delta x = \frac{(\mu - 1) t \delta x}{\lambda}

now plug in all values in it

0.37 = \frac{(1.79 - 1) t}{411 \times 10^{-9}}

t = 0.192 \times 10^{-6} m

t = 0.192 \mu m

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You are holding one end of an elastic cord that is fastened to a wall 3.0 m away. You begin shaking the end of the cord at 2.3 H
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Answer:

Time take to fill the standing wave to the entire length of the string is 1.3 sec.

Explanation:

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Standing wave is the example of the transverse wave, standing wave doesn't transfer energy in a medium.

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also, ∴ v=\frac{x}{t}

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