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densk [106]
3 years ago
13

8. A baseball is hit upward and travels along a parabolic arc before it strikes the se

Physics
1 answer:
Usimov [2.4K]3 years ago
8 0

d. The x-component of the velocity of  the ball is the same througout the  ball's flight

Explanation:

The motion of the baseball is a projectile motion, which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction.

From this description, we can already see that the correct statement is D: in fact, there is no force acting in the horizontal direction on the ball (if we neglect air resistance), therefore the acceleration in the x-direction is zero, therefore the x-component of the velocity is constant.

The other statements are wrong because:

a.  The acceleration of the ball  decreases as the ball moves upward. --> false because the acceleration remains the same (g=9.8 m/s^2 downward)

b.  The velocity of the ball is zero m/s  when the ball is at the highest point  in the arc.​ --> false because only the y-component of the ball's velocity is zero at the highest point, but the x-component is not zero

c. The acceleration of the ball is zero  m/s when the ball is at the highest  point in the arc. --> false because the  acceleration remains the same (g=9.8 m/s^2 downward)

Therefore the correct answer is

d. The x-component of the velocity of  the ball is the same througout the  ball's flight

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

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5 0
2 years ago
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What two motions combine to produce an orbit?
Ivenika [448]

I'm pretty sure it's Inertia and Gravity

Inertia deals with an object's tendency to stay in motion at a constant speed.


Hopefully this helped and good luck.

8 0
3 years ago
A truck using a rope to tow a 2230-kg car accelerates from rest to 13.0 m/s in a time of 15.0s. How strong must the rope be? μk
Leokris [45]

Answer:

The rope must have a force of 10084,21 N

Explanation

Acceleration calculation

The car acceleration is equal to the acceleration of the truck

ac: car acceleration\frac{m}{s^{2} }

at: truck acceleration\frac{m}{s^{2} })

ac = at= \frac{vf-vi}{t-ti}  equation(1)

Known information:

vi = Initial speed = 0, ti = initial time = 0

vf = Final speed = 13 \frac{m}{s}, t = final time =5 s

We replaced the known information in the equation(1):

ac = at = \frac{13-0}{15-0}

ac=ac=\frac{13}{15}  \frac{m}{s}

Dynamic analysis

The forces acting on the car are the following:

Wc: Car weight

N: normal force, road force on the car

Ff: Friction force

T: Force of tension

Car weight calculation:

Wc=mc*g

mc = Car mass = 2230kg

g = Gravity acceleration=9.8 \frac{m}{s^{2} }

Wc= 2230*9.8

Wc=21854 N

Normal force calculation:

Newton's first law

sum Fy= 0

N-W=0

N=W

N=21854 N

Friction force calculation (Ff):

We have the formula to calculate the friction force:

Ff = μk * N  Equation (3)

μk kinetic coefficient of friction

We know that μk = 0.373and N= 21854N ,then:

Ff=0.373*21854

Ff=8151.54 N

Calculation of the tension force in the rope (T):

Newton's Second law

sum Fx= mc*ac

T-Ff=mc*ac

T=2230(\frac{13}{15}) + 8151.54

T=10084,21 N

Answer: The rope must have a force of 10084,21 N

8 0
3 years ago
50 kg of water at 75o C is cooled to 25o C. How much heat was given off?
attashe74 [19]

Answer:

b the answer is b

Explanation:

b is the awnser because it cools after the heat on the water witch lets the steam out

8 0
2 years ago
A student pushes on a 5 kg box with a force of 20 N forward. The force of sliding friction
mart [117]

Answer:

Explanation:

F=20N

mu=-10N

F=ma

20-10=10

10=(5)(a)

a=2 m/s^2

4 0
2 years ago
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