Answer:
1.62 L
Explanation:
Charle's law for ideal gases states that for a gas kept at constant pressure, the ratio between volume and temperature is constant:

where in this problem we have
is the initial volume of the gas
is the initial temperature of the gas
is the final volume of the gas
is the final temperature
Solving the equation for V2, we find

<u>Answer</u>:
The coefficient of static friction between the tires and the road is 1.987
<u>Explanation</u>:
<u>Given</u>:
Radius of the track, r = 516 m
Tangential Acceleration
= 3.89 m/s^2
Speed,v = 32.8 m/s
<u>To Find:</u>
The coefficient of static friction between the tires and the road = ?
<u>Solution</u>:
The radial Acceleration is given by,




Now the total acceleration is
=>
=>
=>
=>
The frictional force on the car will be f = ma------------(1)
And the force due to gravity is W = mg--------------------(2)
Now the coefficient of static friction is

From (1) and (2)


Substituting the values, we get


Answer:
See Explanation
Explanation:
The question is incomplete, as there are no diagrams or options to provide more information to the question.
The general explanation is as follows:
For the object not to move
(1): The forces acting on the object must opposite each other. i.e. if force A acts at the right (or positive direction), force B will act at the left (or negative direction).
(2) The two forces must be equal.
So, for instance:
If the pair of forces are 5N and 5N in opposite directions, the object wil not move.
However, if one of the forces is greater, the object will move towards the direction of the greater force.
Answer:
The magnitude of the force is 34.59 N.
Explanation:
Given that,
Inside pressure 
Area 
Outside pressure = 1 atm
We need to calculate the magnitude of the force
Using formula of force


Where,
=inside Pressure
=outside Pressure
A = area
Put the value into the formula


Hence, The magnitude of the force is 34.59 N.
The answer would be (A) Protons