Answer: Acceleration = 5m/s^2; Distance traveled = 320 m
Explanation:
Velocity of car = 40m/s
Time taken = 8 seconds
Acceleration = ?
Distance traveled = ?
A) Since acceleration is the rate of change of velocity per unit time
i.e acceleration = velocity / time
acceleration = 40m/s / 8 seconds
Acceleration = 5m/s^2
B) To get how far the car traveled before stopping, obtain the distance from the formula:
velocity = distance traveled / time
40m/s = distance / 8 seconds
Distance = 40m/s x 8 seconds
Distance = 320 m
Thus, the car’s acceleration is 5m/s^2 while it traveled 320 metres before stopping.
To solve the problem, we
must know the heat capacity of ice and water.
For Cp = 2090 J/kg C
H = mCpT
H = (10 kg) ( 2090 J/ Kg C)
( -23 C)
H = - 480700 J
For water Cp = 4180 j/kg C
H = (100 kg) ( 4180 J/kg C)
( 60 C)
<span>H = 2508000 J</span>
Your mass wouldn’t change, but your weight would. Weight depends on the force of gravity however mass does not. When you land on the moon, your mass is the same as it was on the earth but weight will drop
Answer:
0.43 s
Explanation:
We have the following parameters:
Initial velocity, u = 7.4 m/s
Acceleration of gravity, g = 9.8 
Distance, s = 43 in + 10 ft = 1.092 m + 3.048 m = 4.14 m
Time, t = ?
Using the equation of motion 
, we have
Using the quadratic formula 
where a = 4.9, b = 7.4 and c = - 4.14, and solving for the positive value of t only, we have
s
Answer:
v₂=- 34 .85 m/s
v₁=0.14 m/s
Explanation:
Given that
m₁=70 kg ,u₁=0 m/s
m₂=0.15 kg ,u₂=35 m/s
Given that collision is elastic .We know that for elastic collision
Lets take their final speed is v₁ and v₂
From momentum conservation
m₁u₁+m₂u₂=m₁v₁+m₂v₂
70 x 0+ 0.15 x 35 = 70 x v₁ + 0.15 x v₂
70 x v₁ + 0.15 x v₂=5.25 --------1
v₂-v₁=u₁-u₂ ( e= 1)
v₂-v₁ = -35 --------2
By solving above equations
v₂=- 34 .85 m/s
v₁=0.14 m/s
