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Alenkasestr [34]
3 years ago
12

Please need help on this one

Physics
1 answer:
Lana71 [14]3 years ago
7 0
Tell them to increase the amplitude of their sound waves.
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A student stretches an elastic band by 0.8 m in 0.5 seconds. The spring constant of the elastic band is 40 N/m. What was the pow
miv72 [106K]

Answer:

The power exerted by the student is 51.2 W

Explanation:

Given;

extension of the elastic band, x = 0.8 m

time taken to stretch this distance, t = 0.5 seconds

the spring constant, k = 40 N/m

Apply Hook's law;

F = kx

where;

F is the force applied to the elastic band

k is the spring constant

x is the extension of the elastic band

F = 40 x 0.8

F = 32 N

The power exerted by the student is calculated as;

P = Fv

where;

F is the applied force

v is velocity = d/t

P = F x (d/t)

P = 32 x (0.8 /0.5)

P = 32 x 1.6

P = 51.2 W

Therefore, the power exerted by the student is 51.2 W

3 0
3 years ago
Which of the following is a base?<br><br> A. Lemon Juice<br> B. Baking Soda<br> C. Vinegar
natali 33 [55]
Answer:
B
Explanation
Because you put baking soda first then vinegar which makes it bubble and rise hope this helps
6 0
3 years ago
Water can fall as precipitation, which may include rain, snow, or hail is an observation or inference?
lukranit [14]

THe best answer would be observation because you can see that all 3 are made up of water which you don't need to infer because you have the proof when you look at all 3 different types of precipitation.

I hope this helps you out.

7 0
3 years ago
Hydrogen is a pure substance represented by the chemical symbol . Which of the following best describes hydrogen?
PolarNik [594]

Answer:

D.Hydrogen is a compound made of two or more kinds of atoms.

4 0
3 years ago
An airplane is traveling at a fixed altitude with an outside wind factor. The airplane is headed N 40° W at a speed of 600 miles
bija089 [108]

Answer:\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]

Explanation:

Given

Plane is initially flying with velocity of magnitude v=600\ mph

at angle of 40^{\circ} with North towards west

Velocity of plane airplane can be written as

v_a=600(-\sin 40\hat{i}+\cos 40\hat{j})

Now wind is encountered with speed of v=80\ mph at angle of N45^{\circ}E

v_w=80(\cos 45\hat{i}+\sin 45\hat{j})

resultant velocity

\vec{v_R}=\vec{v_a} +\vec{v_w}

\vec{v_R}=600(-\sin 40\hat{i}+\cos 40\hat{j})+ 80(\cos 45\hat{i}+\sin 45\hat{j})

\vec{v_R}=\hat{i}[-385.67+56.56]+\hat{j}[459.62+56.56]

\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]

for direction \tan \theta =\frac{516.18}{329.11}

\tan \theta =1.568

\theta =57.47^{\circ} west of North

3 0
3 years ago
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