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laila [671]
3 years ago
9

HELP PLEASE I WILL GIVE 13 POINTS

Mathematics
1 answer:
kenny6666 [7]3 years ago
3 0

Answer:

this difference indicates that the results are independent but not reliable.

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Jordan will hike the trail shown at a rate of 4 ​mi/h. Write a linear equation to represent the distance Jordan still has to wal
dangina [55]

Answer:

Y=25-4x

Y means the distance Jordan still has to walk after x hour

4 0
2 years ago
65536, 256, 16, What is the next number?
Oduvanchick [21]
Hello,

x_{1} =65536\\
 x_{n+1} =\sqrt{ x_{n}}\\\\

 x_{1}=65536\\
 x_{2} =\sqrt{65536}=256\\
 x_{3} =\sqrt{256}=16\\
 x_{4} =\sqrt{16}=4\\
 x_{5} =\sqrt{4}=2\\
 x_{6} =\sqrt{2}\\
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7 0
3 years ago
Brewed decaffeinated coffee contains some caffeine. We want to estimate the amount of caffeine in 8 ounce cups of decaf coffee a
rusak2 [61]

Answer:

We would have to take a sample of 62 to achieve this result.

Step-by-step explanation:

Confidence level of 95%.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Assume that the standard deviation in the amount of caffeine in 8 ounces of decaf coffee is known to be 2 mg.

This means that \sigma = 2

If we wanted to estimate the true mean amount of caffeine in 8 ounce cups of decaf coffee to within /- 0.5 mg, how large a sample would we have to take to achieve this result?

We would need a sample of n.

n is found when M = 0.5. So

M = z\frac{\sigma}{\sqrt{n}}

0.5 = 1.96\frac{2}{\sqrt{n}}

0.5\sqrt{n} = 2*1.96

Dividing both sides by 0.5

\sqrt{n} = 4*1.96

(\sqrt{n})^2 = (4*1.96)^2

n = 61.5

Rounding up

We would have to take a sample of 62 to achieve this result.

8 0
3 years ago
Frank thinks he will need at about 12 1/2 kilograms of sand for sandbox he is building. The sand he wants is 3$ per kilogram. Ab
vesna_86 [32]
12 * 3 = 36, 1/2 * 3 = 1 1/2
36 + 1 1/2 = $37.50 for about 13 kilograms of sand.
4 0
3 years ago
Lily is using wrapping paper to cover a box with dimensions 7 centimeters by 10 centimeters by 5 centimeters. What is the least
Leto [7]
Answer: 310 centimeters square of paper

Explanation: to find the answer you need to know the surface area of the box. So you use the formula SA = 2ab+2bc+2ac
A=7
B=10
C=5
After inputting the values you get:
SA = 2(7)(10) + 2(10)(5) + 2(7)(5)
and after simplifying:
SA = 140+100+70
SA=310
4 0
3 years ago
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