HELP PLEASE I WILL GIVE 13 POINTS

pochemuha

$\frac{1}{6}$ ÷ $\frac{2}{6}$

First, apply this following rule: $a$ ÷ $\frac{b}{x} = a$ × $\frac{c}{b}$
$\frac{1}{6}$ × $\frac{6}{2}$
Second, apply this following rule: $\frac{a}{b}$ × $\frac{c}{d} = \frac{ac}{bd}$
$\frac{1x6}{6x2}$
Third, multiply 1 × 6 to get 6 and 6 × 2 to get 12.
$\frac{6}{12}$
Fourth, find the GCF of 6 and 12.
Factors of 6: 1, 2, 3, 6
Factors of 12: 1, 2, 3, 4, 6, 12
The GCF is 6.
Fifth, divide the numerator by the GCF.
$6$ ÷ $6 = 1$
Sixth, divide the denominator by the GCF.
$12$ ÷ $6 = 2$
Seventh, collect the new numerator and new denominator.
$\frac{1}{2}$

Answer as fraction: $\frac{1}{2}$
Answer as decimal: 0.5

8 0

3 years ago

WILL MARK BRAINLIEST IF CORRECT

RideAnS [48]

The answer would be “D” because it’s is 4 less than 7j.

7 0

3 years ago

Which expression is equal to x−5x2+3−x2−x+4x2+3 ?

insens350 [35]

the third option. I think

8 0

2 years ago

An expression is shown below: 2x3y + 18xy − 10x2y − 90y Part A: Rewrite the expression by factoring out the greatest common fact

SCORPION-xisa [38]

Answer:

Part A : 2y( x³ + 9x - 5x² - 45 ), Part B : 2y( x - 5 )( x² + 9 )

Step-by-step explanation:

Part A : Let's break every term down here to their " prime factors ", and see what is common among them,

2x³y + 18xy − 10x²y − 90y -

2x³y = 2 $*$ x³ $*$ y,

18xy = 2 $*$ 3 $*$ 3 $*$ x $*$ y,

− 10x²y = 2 $*$ - 5 $*$ x² $*$ y, - so as you can see for this example I purposely broke down - 10 into 2 and - 5. I could have placed the negative on the 2, but as that value was must likely common among all the terms, I decided to place it on the 5. The same goes for " − 90y. " I placed the negative there on the 5 once more.

− 90y = 2 $*$ - 5 $*$ 3 $*$ 3 $*$ y

The terms common among each term are 2 and y. Therefore, the GCF ( greatest common factor ) is 2x. Let's now factor the expression using this value.

2y( x³ + 9x - 5x² - 45 )

Part B : Let's simply factor this entire expression. Of course starting with the " factored " expression : 2y( x³ + 9x - 5x² - 45 ),

$2y\left(x^3+9x-5x^2-45\right)$ - Factor out " $(x^3+9x-5x^2-45\right))$ " by grouping,

$\left(x^3-5x^2\right)+\left(9x-45\right)$ - Factor 9 from 9x - 45 and x² from x³ - 5x²,

$9\left(x-5\right)+x^2\left(x-5\right)$ - Factor out common term x - 5,

$\left(x-5\right)\left(x^2+9\right)$ - And our solution is thus 2y( x - 5 )( x² + 9 )

3 0

3 years ago

three tanks are capable of holding 108 litres, 168 litres and 180 litres of milk. determine the capacity of the greatest vessel

SpyIntel [72]

A vessel of 7,560 liters

Step-by-step explanation:

This means finding the Least Common Multiple for;

108 168 180

We begin by finding the multiples of each number;

Multiples of 108:

108, 216, 324, 432, 540, 648, 756, 864, 972, 1080, 1188, 1296, 1404, 1512, 1620, 1728, 1836, 1944, 2052, 2160, 2268, 2376, 2484, 2592, 2700, 2808, 2916, 3024, 3132, 3240, 3348, 3456, 3564, 3672, 3780, 3888, 3996, 4104, 4212, 4320, 4428, 4536, 4644, 4752, 4860, 4968, 5076, 5184, 5292, 5400, 5508, 5616, 5724, 5832, 5940, 6048, 6156, 6264, 6372, 6480, 6588, 6696, 6804, 6912, 7020, 7128, 7236, 7344, 7452, 7560, 7668, 7776

Multiples of 168:

168, 336, 504, 672, 840, 1008, 1176, 1344, 1512, 1680, 1848, 2016, 2184, 2352, 2520, 2688, 2856, 3024, 3192, 3360, 3528, 3696, 3864, 4032, 4200, 4368, 4536, 4704, 4872, 5040, 5208, 5376, 5544, 5712, 5880, 6048, 6216, 6384, 6552, 6720, 6888, 7056, 7224, 7392, 7560, 7728, 7896

Multiples of 180:

180, 360, 540, 720, 900, 1080, 1260, 1440, 1620, 1800, 1980, 2160, 2340, 2520, 2700, 2880, 3060, 3240, 3420, 3600, 3780, 3960, 4140, 4320, 4500, 4680, 4860, 5040, 5220, 5400, 5580, 5760, 5940, 6120, 6300, 6480, 6660, 6840, 7020, 7200, 7380, 7560, 7740, 7920

The Least Common Multiple for the 3 number is;

= 7560

Therefore a vessel of 7,560 liters fills each one of them an exact number of times with no remainder.

Learn More:

For more on Least Common Multiple check out;

brainly.com/question/11978021

#LearnWithBrainly

5 0

3 years ago