Select the correct locations on the image.

Mathematics

1 answer:

Semenov [28]2 years ago

8 0

This has to be done by hit and trial method. i.e. you have to checking adding which of the function from first column to function in second column will yield h(x).

The following functions yield given value of h(x).

f(x) = -2x + 3
g(x) = 7x - 9

f(x) + g(x) = -2x +3 + 7x - 9
f(x) + g(x) = 5x -6 = h(x)

So, from 1st column its the cell number 3, and from the second column its the cell number 2.

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The dimensions of a conical funnel are shown below: A conical funnel is shown with the height of the cone as 8 inches and the ra

ELEN [110]

Answer:

Step-by-step explanation:

r=3 in

h=8 in

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2 years ago

Read 2 more answers

What is the value of x in the figure above? ^^

Zielflug [23.3K]

First solve for the other angles.
You know one angle is 15º.
The one across from it is also 15º since it is a vertical angle to the known 15º angle.
Both of those together gets 30º.
The whole thing is 360º, so just subtract 30 from 360 and divide.
360 - 30 = 330
Do the same for the 15x angle.
The one under/across to it is a vertical angle so is also 15xº.
Now you are left with 30xº = 330.
Just divide now.
330 / 30 = 11
x = 11
15x = 165

Checking your work:
15x = 165
15x = 165
15
15
Those are the angles.
Add those numbers together and make sure it adds up to 360º.
165 + 165 + 15 + 15 = 360
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3 years ago

A solid right pyramid has a regular hexagonal base with an area of 7.4 units2. The pyramid has a height of 6 units.

Lelechka [254]

Answer: Second option.

Step-by-step explanation:

You need to use the following formula:

$V=\frac{1}{3}Bh$

Where "B" is the area of its base and "h" is the height.

According to the data given in the exercise, you know that:

$B=7.4 units^2\\\\h=6\ units$

Therefore, knowing this values, you can substitute them into the formula shown before and then evaluate, in order to calculate the volume of thi right pyramid whose base is a regular hexagon.

Then, you get:

$V=\frac{1}{3}(7.4 units^2)(6\ units)\\\\V=14.8\ units^3$