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3 years ago

Select the correct locations on the image.

Mathematics

1 answer:

Semenov [28]3 years ago

8 0

This has to be done by hit and trial method. i.e. you have to checking adding which of the function from first column to function in second column will yield h(x).

The following functions yield given value of h(x).

f(x) = -2x + 3
g(x) = 7x - 9

f(x) + g(x) = -2x +3 + 7x - 9
f(x) + g(x) = 5x -6 = h(x)

So, from 1st column its the cell number 3, and from the second column its the cell number 2.

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Step by step show answer for problem 3-3×6+2

storchak [24]

Do it according to the order of operations
(P)E^MxD/A+S-
the answer would be -13

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3 years ago

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Which table represents the graph of a logarithmic function in the form y=log3x when b>1?

alex41 [277]

Answer:

The satisfied table of the given function $y = log_{b} (x)$

x 1/8 1/4 1/2 1 2

y -3 -2 -1 0 1

Step-by-step explanation:

Explanation :-

Given logarithmic function $y = log_{b} (x)$ if b >1

Given first table

put x = $\frac{1}{8}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{8} )$

$y = log_{2} (2^{-3} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-3} ) = -3 log_{2} (2) = -3 (1) = -3$

y = -3

ii)

put x = $\frac{1}{4}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{4} )$

$y = log_{2} (2^{-2} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-2} ) = -2 log_{2} (2) = -2 (1) = -2$

y = -2

iii)

put x = $\frac{1}{2}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{2} )$

$y = log_{2} (2^{-1} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-1} ) = -1 log_{2} (2) = - (1) = -1$

y = -1

iv)

put x = 1 given b > 1 so we can choose b = 2

$y = log_{2} (1 )$ = 0

y = 0

v)

put x = $2$ given b > 1 so we can choose b = 2

$y = log_{2} (2 )$

y = 1

Final answer:-

The satisfied table of the given function

x 1/8 1/4 1/2 1 2

y -3 -2 -1 0 1

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3 years ago

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D=ABC for A solve for A

Dafna1 [17]

A = D/BC. In order to isolate A, all you do is divide by BC

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3 years ago

*Help ASAP Please! Studying for finals and I'm stuck on this question!*

Nezavi [6.7K]

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3 years ago

Find the decay factor from the equation y = 453(0.87)^4

dybincka [34]

The decay factor of the equation given in the task content is; 0.87.

<h3>What is the decay factor from the equation?</h3>

According to the task content; the equation given is; y = 453(0.87)^4.

By comparison with exponential decay functions, it follows that the decay factor from the equation given is; 0.87 which insinuates that the factor of change after each decay is 0.87.