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ella [17]
4 years ago
8

Simplify (5rs-1t3)(-3r2st).

Mathematics
1 answer:
maxonik [38]4 years ago
7 0
(5rs-1t3)(-3r2st)

-30r^2s^2t+18rst^2
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Solve the inequality below, then determine which number line shows the solution graphed correctly.
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Answer:

Line B

Step-by-step explanation:

2x-6<2

+6 +6

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It's Number Line B. All symbols are supposed to be less than or equal to, just don't have that symbol on my keyboard.

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3 years ago
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Charles bought 24 blow-pops for $7.20. His little sister Tracy wants 11 blow-pops. How much will 11 blow-pops cost?
Norma-Jean [14]

$3.30 because taking the cost of 24, which is $7.20, and dividing is by the amount, 24, you get that one Blow-Pop costs $0.30. Then to find how many 11 costs you just need to multiply $0.30 by 11, and you get $3.30.

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4 years ago
To fit between two windows, the width of a bookshelf must be no greater than 6 1/2feet. Mrs.aguilar purchases a bookshelf that i
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3 years ago
The smallest object visible with your eyes is similar to the width of a piece of hair, which is 1×10−4 meters wide. Using an opt
Sloan [31]

Answer:

B. 5\times10^{2}

Step-by-step explanation:

We are told that the smallest object visible with our eyes is similar to the width of a piece of hair, which is 1\times 10^{-4} meters wide.

Using an optical microscope, we can see items up to 2\times 10^{-7} meters wide.

To find the objects we can see with our eyes are how much larger than the objects we can see with an optical microscope, we can set an equation as:

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1*10^{-4}}{2*10^{-7}}

Using the exponent rule of quotient \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1}{2}*10^{-4-(-7)}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{-4+7}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{3}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10\times 10^{3-1}

\text{The object we can see with our eyes}=5\times10^{2}*\text{The objects we can see with microscope}

Therefore, the objects we can see with our eyes are 5\times10^{2} times larger than the objects we can see with an optical microscope and option B is the correct choice.

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3 years ago
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Rasek [7]
Hey You!

32 / 8 = 4

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Numerator;Denominator

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439 / 3 = 146.3333 repeat.

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