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Nadusha1986 [10]
2 years ago
13

Help? this counts as a grade so i really need help

Mathematics
1 answer:
morpeh [17]2 years ago
7 0
15c=m

15 x (amount of cars) = amount of money
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If the price of a bag of Ritz peanut butter crackers increases from $0.70 to $0.80, what it the percent increase?
Shtirlitz [24]

Answer:

14%

Step-by-step explanation:

To get the percent increase divide 0.8 by 0.7

0.8/0.7 ≈ 1.14285714286

So the percent increase would by about 14 percent

3 0
2 years ago
Does anyone know the answers to this ? Pls help me out
Reptile [31]

Answer:

C. 4

Step-by-step explanation:

2x³+2x¹+2x+5+4/x-1

5 0
2 years ago
Factor the polynomial completely 6x^2-3x+2
fenix001 [56]

Answer:

can't be factored

answer is D

7 0
2 years ago
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Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
2 years ago
Will give brainliest to correct answer
nordsb [41]

Answer:

The answer is b

Step-by-step explanation:

6 0
2 years ago
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