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Usimov [2.4K]
3 years ago
14

I need help with this! I'm giving branliest! 6/2 (1+2)

Mathematics
2 answers:
shusha [124]3 years ago
7 0

Answer:

9

Step-by-step explanation:

frez [133]3 years ago
6 0

Answer:

9

Step-by-step explanation:

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The cheetah area at a zoo is designed in a triangular fashion, surrounded on all three sides by sidewalks. The property has 67 f
Strike441 [17]

1529.3 square unit is the area of the cheetah area at a zoo is designed in a triangular fashion, surrounded on all three sides by sidewalks, given that the property has 67 feet of frontage on one sidewalk, and 48 feet of frontage on another; these two sidewalks intersect at a 72° angle. This can obtained by using the formula of Area of a Triangle with 2 Sides and Included Angle.

<h3>Find the area of the cheetah area at the zoo:</h3>

Area of a triangle is obtained using the formula of Area of a Triangle with 2 Sides and Included Angle.

If in a triangle ΔABC,

  • 1/2 × bc × sin(A), if b and c are two sides of a triangle and angle A is the included angle
  • 1/2 × ac × sin(B), if a and c are two sides of a triangle and angle B is the included angle
  • 1/2 × ab × sin(C), if a and b are two sides of a triangle and angle C is the included angle

Here it is given that,

67 feet and 48 feet are the sides of the triangular space and angle 72° is the included angle.

By using the formula of Area of a Triangle with 2 Sides and Included Angle,

Area of the cheetah area = 1/2 × bc × sin(A)

Area of the cheetah area = 1/2 × (67)(48) × sin(72°)

sin(72°) = 0.951056516

Area of the cheetah area = 1608 × 0.951056516

Area of the cheetah area = 1529.29888 ≈ 1529.3 square unit

             

Hence 1529.3 square unit is the area of the cheetah area at a zoo is designed in a triangular fashion, surrounded on all three sides by sidewalks, given that the property has 67 feet of frontage on one sidewalk, and 48 feet of frontage on another; these two sidewalks intersect at a 72° angle.

   

Learn more about area of triangle here:

brainly.com/question/19305981

#SPJ1

7 0
2 years ago
Subtract 2m – 7q + 5 from 4p + 2q and add your result to 7m² - 3m + 9q – 1
max2010maxim [7]

212134568899999999love is love

7 0
3 years ago
Read 2 more answers
10 points || answer ASAP if you can
dmitriy555 [2]

Answer:

It would affect the mean, range, and standard deviation

Step-by-step explanation:

I got this right on the test :)

8 0
3 years ago
What is equivelint in ratio
fgiga [73]
A equivelint  ratio is when u can multi or divide by both sides
6 0
3 years ago
A car insurance company has determined that 9% of all drivers were involved in a car accident last year. among 14 drivers living
andriy [413]

The probability of getting 3 or more who were involved in a car accident last year is 0.126.

Given 9% of the drivers were involved in a car accident last year.

We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.

We have to use binomial theorem which is as under:

nC_{r}p^{r} (1-p)^{n-r}

where p is the probability an r is the number of trials.

Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]

=1-{14C_{0}0.9^{0} (0.1)^{14} +14C_{1} (0.9)^{1} (0.1)^{13} +14C_{2} (0.9)^{2} (0.1)^{12}}

=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}

=1-{0.2670+0.3654+0.2358}

=1-0.8682

=0.1318

Among the options given the nearest is 0.126.

Hence the probability that 3 or more are involved in the accident is 0.126.

Learn more about probability at brainly.com/question/24756209

#SPJ4

7 0
2 years ago
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