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denis-greek [22]
3 years ago
7

Will give brainly to those who help me!!!

Engineering
1 answer:
cluponka [151]3 years ago
5 0

Answer:

i will help you as long a you need

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Create a program named IntegerFacts whose Main() method declares an array of 10 integers.Call a method named FillArray to intera
musickatia [10]

Answer:

C# codee

using System;

class IntegerFacts

{

static void Main()

{

int[] x = new int[10];

int sum = 0;

int siz = 0, high = 0, low = 0, avg = 0;

siz = FillArray(x);

Statistics(x, ref high, ref low, ref sum, ref avg, siz);

Console.Write("The highest value is " + high);

Console.Write("\nThe lowest value is " + low);

Console.Write("\nThe sum of the values is " + sum);

Console.Write("\nThe average is " + avg);

}

static void Statistics (int [] b, ref int h, ref int l, ref int s, ref int a, int size)

{

if (size == 0)

h = l = s = a = 0;

else

{

int i =0;

l = 999;

h = 0;

s = 0;

for (; i < size;++i)

{

if(b[i] > h)

h = b[i];

if(b[i] < l)

l = b[i];

s += b[i];

}

a = s / size;

}

}

static int FillArray (int[] a)

{

int i = 0, count = 0;

int intTemp =0 ;

string temp;

for(i = 0 ; i < 10 ; i++)

{

Console.Write("Enter element number"+(i+1) +" : ");

temp = Console.ReadLine();

if (int.TryParse(temp, out intTemp)) {

if (intTemp != 999)

{

a[i] = intTemp;

count++;

}

else

break;

}

else

{

Console.Write("\n\nOops.. You entered a wrong number. Try again \n\n");

i--;

}

}

return count;

}

}

Explanation:

The output of the above program is given in the attached file.

8 0
4 years ago
Air is to be compressed so that its volume is reduced to half of its original volume if the initial pressure is 200 kPa and the
Alex_Xolod [135]

Answer:

P_{2} = 527.803\,kPa

Explanation:

The politropic relationship for a isentropic process is:

\frac{P_{2}}{P_{1}} = \left(\frac{V_{1}}{V_{2}}  \right)^{\gamma}

Where \gamma is the ratio of specific heats

The final pressure is:

P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}}\right)^{\gamma}

P_{2} = (200\,kPa)\cdot (2)^{1.4}

P_{2} = 527.803\,kPa

7 0
3 years ago
an electric circuit includes a voltage source and two resistances (50 and 75) in parallel. determine the voltage source required
ASHA 777 [7]

Answer:

The voltage source required to provide 1.6 A of current through the 75 ohm resistance is 120 V.

Explanation:

Given;

Resistance, R₁ = 50Ω

Resistance, R₂ = 75Ω

Total resistance, R = (R₁R₂)/(R₁ + R₂)

Total resistance, R = (50 x 75)/(125)

Total resistance, R = 30 Ω

According to ohms law, sum of current in a parallel circuit is given as

I = I₁ + I₂

I = \frac{V}{R_1} + \frac{V}{R_2}

Voltage across each resistor is the same

1.6 = \frac{V}{R_2}  

V = 1.6 x R₂

V = 1.6 x 75

V = 120 V

Therefore, the voltage source required to provide 1.6 A of current through the 75 ohm resistance is 120 V.

This voltage is also the same for 50 ohms resistance but the current will be 2.4 A.

3 0
3 years ago
Read 2 more answers
The in situ moisture content of a soil is 18% and the moist (total) unit weight is 105 pcf. The soil is to be excavated and tran
densk [106]

Answer: Volume= 1.16 yd³

Explanation:

We are given the in-situ moisture content= 18% and moist unit weight= 105 pcf

First we find out the dry unit weight

Dry unit weight= Moist unit weight / (1+ moisture content)

Dry unit weight= \frac{105}{1.18}

Dry unit weight= 88.983 pcf

Now, to find the volume ( in terms of each cubic yard i.e 1 yd³ we have

Volume = Dry unit weight compacted / Dry unit weight (in-situ) * 1 yd³

Volume= \frac{103.5}{88.983} * 1

Volume= 1.16 yd³

6 0
4 years ago
The moons light-colored highlights are
gulaghasi [49]
The light colored material in areas of the mood is the earliest crust on the moon.
3 0
3 years ago
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